Here’s the answer, you should prompt for input, then check the input using a while loop instead of IF-ELSE to make sure the user provided the answer you desired. This is actually a simple logic question tho. You may explore do-while loop too. #include <iostream> using namespace std; int main() { string item; float price; … Read more
I don’t know how you designed your models but you can follow this way: class Person { String name; Integer age; List<Address> addressList; // getter, setter, const… } class Address { // some fields… // getter, setter, const… } And then you can add your address to your person via add method: Person p = … Read more
I think your code is not saved. Do Ctrl+S and then try running it again. solved I am very much new at coding in c++ i can not setup vs code giving error [closed]
You need to verify that x is not undefined in case none of the elements have the class your looking for var x = document.getElementsByClassName(“check”)[0] if (x) { var y = window.getComputedStyle(x).display alert(y) } else { alert(‘not found’) } solved How do i get just 1 element JS [closed]
You may do: # data head(iris) Sepal.Length Sepal.Width Petal.Length Petal.Width Species 1 5.1 3.5 1.4 0.2 setosa 2 4.9 3.0 1.4 0.2 setosa 3 4.7 3.2 1.3 0.2 setosa 4 4.6 3.1 1.5 0.2 setosa 5 5.0 3.6 1.4 0.2 setosa 6 5.4 3.9 1.7 0.4 setosa the function foo_divide <- function(x, y){ foo <- … Read more
$db is not available within the function scope, you could Pass $db as an argument function func($db, $query, $params){ return $db->db_control($query, $params); } $results = func($db, $query, $params); Or function func($query, $params){ global $db; return $db->db_control($query, $params); } $result = func($query, $params); Use global to make it available within the function, there’s probably other solutions … Read more
The correct link to the docs is https://developer.android.com/reference/android/telephony/CellInfoNr The way to get docs corrected is to report the error to the author, not by posting a question on StackOverflow. The link for doc errors is https://issuetracker.google.com/issues/new?component=192697 1 solved I guess I found a typo on android documentation [closed]
Division is defined so that the following is always true n = q × d + r where n is the numerator (or dividend), d != 0 is the denominator (or divisor), q is the quotient, and r > 0 is the remainder. (This holds for positive and negative values; q is positive if n … Read more
CLLocationManager() has distanceFilter and pausesLocationUpdatesAutomatically. You can add a distanceFilter to “ignore” positions and set pausesLocationUpdatesAutomatically to true. If you are using location for navigation don’t hesitate to use kCLLocationAccuracyBestForNavigation 3 solved Location Tracking bouncing the current location and by default drawing the route
From the C Standard (6.4.5 String literals) 7 It is unspecified whether these arrays are distinct provided their elements have the appropriate values. If the program attempts to modify such an array, the behavior is undefined. As for your statement. The second paragraph says that “C does not strictly prohibit modifying string literals” while compilers … Read more
For starters you could just run the code… but otherwise we can try and predict the output. For starters the function f has two parameters, i and j. The & Infront of the j means that the value of the function input is passed by reference (the value of the variable will be edited). So … Read more
So, going the VBA route, you’ll need to loop through each row in your tab and test the value to see if it’s a duplicate, if it’s a duplicate then you’ll increase a counter variable and once that counter variable hits 3 you start deleting rows. This is a little complicated if you haven’t worked … Read more
You could split over a specific string (degree character for example), store in a String array and parse the first element. Something like this: String str = “47°C” String[] strArray = str.split(“°”); int number = Integer.parseInt(strArray[0]); solved I have a string with a number and a letter, is there a way to move the integer … Read more
The easiest way to display information gathered from the chat is to send back channel events from the bot with the data and then intercept the message with a custom activity middleware in WebChat. Then you can process the data on the webpage however you’d like. Bot – NodeJs SDK v4 In the bot, we … Read more
In the first line you have written first_quadrant as 1 which is an integer. In the second line you are trying to use a for loop over an integer. This is not allowed and therefore the error. You could do it in many other ways. I am writing two such possible solutions. Solution 1 first_quadrant … Read more