You could try this. String nbr = input.nextLine(); int a=nbr.charAt(0)-‘0’; int b=nbr.charAt(1)-‘0’; int c=nbr.charAt(2)-‘0’; Also, you could use substring and parse the result Using Integer.parseInt int a=Integer.parseInt(nbr.substring(0,1)); //Contains the leftmost digit 2 solved How do I select the first, second, or third digit from a String containing three digits? [closed]
res = [] for item in s.split(‘ ‘): … try: … int(item) … res.append(item) … except: … res += list(item) 5 solved How to separate string and integers to a list [closed]
The second argument tells int the base of the input string. From the help: class int(object) | int(x=0) -> integer | int(x, base=10) -> integer | | Convert a number or string to an integer, or return 0 if no arguments | are given. If x is a number, return x.__int__(). For floating point | … Read more
Define a struct with all the correct types and order. Point the struct to the data. Then just access the items via the struct elements. Be careful with the types, it is probably best to use well defined types such as int8_t, uint8_t, uint16_t, int16_t, etc to insure the correct element size. You will want … Read more
You can use sprintf or snprintf. int c = 4; char tin [Some_Length]; sprintf(tin , “%d”, c); Or snprintf(tin , Some_Length, “%d”, c); Also, there is no string type in C. 1 solved How To assign a number in a integer variable to a string
The comment in the link says “integer, pointer and member pointer template parameters aren’t lvalues” (emphasis mine). It does not say that named integer variables are not lvalues – they are. If there were such a thing as floating-point template parameters, then they wouldn’t be lvalues either; but named floating-point variables still would be. solved … Read more
If you want to know if the result of dividing a $dividend by a $divisor is going to be a whole number or a number with a fractional portion, you can test that condition first: if (my $remainder = $dividend % $divisor) { print “$dividend cannot be divided evenly by $divisor.”, ” There is a … Read more
The error message tells you that an expression is expected at a certain point in your code: calcNumbers(myArr[missing expression here ], type); Why is that? Because operator[] takes an argument (traditionally an index), as in myArr[1]. No argument, no compile. Note that this error occurs when you are using myArr. You have other places where … Read more
In Java 8 streams, you can generate a stream of integers between two numbers using: IntStream.range(lower, upper)… If you want them to be randomised, then you can use: Random random = new Random(); random.ints(count, lower, upper)… You can then use methods such as forEach, reduce or collect to do something with the stream. So, for … Read more
you can do the following: explanation for the code: Square is formed of 2 equal sides, so in order to draw the square using *, you will think of it like a matrix you need a loop to draw the rows and another loop to draw the columns, and both loop has upper limit which … Read more
This should fix your problem. It will parse all rows and place each line in a string stream. It then parses the string stream and streams the elements into doubles. It should work for any combination of rows and column elements. #include <iostream> #include <fstream> #include <string> #include <sstream> #include <vector> using namespace std; int … Read more
It helps to read the documentation, that would have told you queue<int> q; … int cur = q.front(); q.pop(); solved Assign first item of queue to int [closed]
The program has following issues: Array indexing is wrong : Array is of size 5 starting from 0 , you can use only till a[4] , but for scanf() , it tries to read value as &a[5]. No use of for loop when you are using hard coded index a[1],a[2],etc. Instead the below code will … Read more
I would prefer i++ over the other two because it expresses a common idiom. Those lines of code all end up doing exactly the same thing. But if I’m scanning code for an increment, the ++ just sort of jumps off the page. Also, the i = i++ is actually incorrect. You meant i = … Read more
Well, this piece of code int c; while ((c = getchar()) != EOF && c != ‘\n’); is used to clear the buffer, as mentioned in @napnac’s answer. It is mainly used instead of fflush (stdin);, which is UB. But note that this is successful only if the input buffer happens to contain data ending … Read more