## [Solved] JAVA casting list of strings to string array [duplicate]

Use it like this – String [] myArray = myList.toArray(new String[myList.size()]); solved JAVA casting list of strings to string array [duplicate]

## [Solved] How to print last deleted element from the list? [closed]

my_list = [1, 2, 5, 8, 15, 25] deleted_elements = [] deleted_elements.append(my_list.pop()) deleted_elements.append(my_list.pop()) deleted_elements.append(my_list.pop()) print(my_list) print(deleted_elements) print(“Last deteleted: ” + str(deleted_elements[-1])) solved How to print last deleted element from the list? [closed]

## [Solved] Sort list on 3 values [closed]

You can use OrderBy followed by ThenBy. var result = MyCollection.OrderBy(x => x.CategoryCounter) .ThenBy(y => y.GroupCounter) .ThenBy(z => z.QuestionCounter); 1 solved Sort list on 3 values [closed]

## [Solved] How to find the nearest element in a list [closed]

Use pos = my_list.index(‘asd’) nearest = my_list[pos + 1] Note pos is 3 for the 4th element as Python is 0- based. Note avoid using list for variables as this name has a special meaning in Python. 1 solved How to find the nearest element in a list [closed]

## [Solved] List with sublists inside [closed]

>>> from random import randint >>> n = 10 >>> a = *n // initialise array a wwith exactly n zeros >>> a [0, 0, 0, 0, 0, 0, 0, 0, 0, 0] >>> i = randint(0,n-1) // get random number from 0 to n-1 >>> i 1 >>> a[i]=n //assign a[i] to n >>> … Read more

## [Solved] Need Someone That Can Read This VBA Script! Fairly Simple [closed]

Public Sub MakeColumnsFromRows() Dim totalCutsToMake As Integer Dim currentColumn As Integer Dim currentCut As Integer Dim rowsToCut As Integer Sheets(4).Activate rowsToSkip = 10 totalCutsToMake = (ActiveSheet.UsedRange.Rows.Count / rowsToSkip) currentColumn = 1 Dim RowCount As Integer For currentCut = 1 To totalCutsToMake RowCount = Cells(Rows.Count, currentColumn).End(xlUp).Row Range(Cells(rowsToSkip + 1, currentColumn), Cells(RowCount, currentColumn + 2)).Select Selection.Cut Cells(1, … Read more

## [Solved] Unit Testing with ForEach [closed]

There is probably a lot you could do, but the first thing to do would be to make it more readable. Perhaps something like this: var nullActivities = from p in partnerList from t in p.Tenants let activity = agent.GetShopActivity(t, startDate, endDate) where activity == null select activity; Assert.Empty(nullActivities); Moreover: you may want to think … Read more

## [Solved] You are given an array consisting of n integers. Print the last two digits of the product of its array values [duplicate]

You can try this (it’s version of Python3): n = int(input()) arr = list(map(int, input().rstrip().split())) result = 1 for num in arr: result = (result * num) % 100 print(“{:02d}”.format(result)) A little bit modify for better algorithm: n = int(input()) arr = list(map(int, input().rstrip().split())) result = 1 for num in arr: result = (result * … Read more

## [Solved] index out of range but is in fact in range [closed]

Well try to debug your code by yourself first. Anyhow for your question Why is this happening? : It gives you error in postCode = split_address because your list has 4 elements 0,1,2,3 and you are accessing the 4th element which is not present.. you don’t have the index thats why it gives you error … Read more

## [Solved] Python List of Dictionaries by Loops

If you want only print the resulting dictionaries, uncomment the print statement (and comment the following 2). d1 = [ {‘index’:’1′,’color’:’red’}, {‘index’:’2′,’color’:’blue’}, {‘index’:’3′,’color’:’green’} ] d2 = [ {‘device’:’1′,’name’:’x’}, {‘device’:’2′,’name’:’y’}, {‘device’:’3′,’name’:’z’} ] result_list = [] for dict1 in d1: merged_dict = dict1.copy() for dict2 in d2: merged_dict.update(dict2) # print(merged_dict) result_list.append(merged_dict.copy()) print(result_list) The result: [{‘name’: ‘x’, ‘device’: … Read more