[Solved] Git Push Error in Android Studio [closed]
Introduction Solution may be you are not login your github account correctly. Login again and try. 4
Introduction Solution may be you are not login your github account correctly. Login again and try. 4
Introduction Solution You can split the string and then iterate over the array. Which results in something like this: String input = “3 12#45#33 94#54#23 98#59#27″; String[] strings = input.split(” “); int size = Integer.parseInt(strings[0]); int[][] result = new int[size][size]; for( int i = 0; i < strings.length – 1; i++ ){ String[] strings2 = … Read more
Introduction The onClick handler is an important part of the Activity class in Android. It is used to handle user interactions with the UI elements of an application. In some cases, it may be necessary to use a custom method for the onClick handler instead of the default one provided by the Activity class. In … Read more
Introduction Java applets are small programs written in the Java programming language that can be embedded into webpages and run in web browsers. If you want to run a Java applet from the command prompt, you can do so by using the Java Runtime Environment (JRE). This article will explain how to run Java applets … Read more
Merge two excel into the third excel using java apache poi concept . And while combining the data it should add the data from left to right [closed] solved Merge two excel into the third excel using java apache poi concept . And while combining the data it should add the data from left to … Read more
You can try the below code to convert string array to string public class JavaApplication20 { public static void main(String[] args) { // TODO code application logic here String test1 = “”; String[] test = {“this”,”this2″}; int length = test.length; //System.out.println(“Length :”+length); for(int i=0; i<length; i++){ //System.out.println(test[i]); test1 += test[i]+”,”; } int len = test1.length(); … Read more
Use Comparable and Comparator as shown below, you can also visit https://www.journaldev.com/780/comparable-and-comparator-in-java-example for further details. import java.util.Comparator; class Employee implements Comparable<Employee> { private int id; private String name; private int age; private long salary; public int getId() { return id; } public String getName() { return name; } public int getAge() { return age; } … Read more
Your first port of call should be the documentation which explains it reasonably clearly: Thrown to indicate that an array has been accessed with an illegal index. The index is either negative or greater than or equal to the size of the array. So for example: int[] array = new int[5]; int boom = array[10]; … Read more
Use it like this – String [] myArray = myList.toArray(new String[myList.size()]); solved JAVA casting list of strings to string array [duplicate]
Use this String[] params = data.split(” “); String firstString = params[0]; split() function will split your whole string using space as delimiter, resulting in array of strings. First element of the array is the string you are looking for. 2 solved Extract specific string from String [closed]
for (int i = 0; i < userInput; i++) { System.out.print(” ” +(i%7)+1); } Assuming it is java code that you are talking about. 2 solved using for loop in repeating number of day [closed]
It seems that you are looking implementation of thread pool. Fortunately JDK has one built-in. Take a look on Exectutors framework. solved Open source Java Thread server [closed]
No this is not valid how ever you can do following: String[] name=new String[]{“h”, “e”, “l”, “l”, “o”}; or String name=new String(new char[]{‘h’, ‘e’, ‘l’, ‘l’, ‘o’}); solved Can we declare the reference variable as String for the char array? [closed]
You do it by actually using the i parameter. private static final String ALPHABET = “abcdefghijklmnopqrstuvwxyz”; public static void binary(int n, String str, int i) { if (i == ALPHABET.length()) return; if (n == 0) { System.out.println(str); return; } binary(n – 1, str + ALPHABET.charAt(i), 0); // next letter starts at beginning of alphabet binary(n, … Read more
A simple test proves the loop indeed works as intended: public static void main(String[] args) { int enemysno = 5; for (int i = 0; i < enemysno; i++) { System.out.println(“lalala ” + i); } } this works fine producing lalala 0 lalala 1 lalala 2 lalala 3 lalala 4 It was kind of obvious, … Read more