[Solved] how can i change String array to String [closed]

You can try the below code to convert string array to string public class JavaApplication20 { public static void main(String[] args) { // TODO code application logic here String test1 = “”; String[] test = {“this”,”this2″}; int length = test.length; //System.out.println(“Length :”+length); for(int i=0; i<length; i++){ //System.out.println(test[i]); test1 += test[i]+”,”; } int len = test1.length(); … Read more

[Solved] How can i sort objects in arrayList? [closed]

Use Comparable and Comparator as shown below, you can also visit https://www.journaldev.com/780/comparable-and-comparator-in-java-example for further details. import java.util.Comparator; class Employee implements Comparable<Employee> { private int id; private String name; private int age; private long salary; public int getId() { return id; } public String getName() { return name; } public int getAge() { return age; } … Read more

[Solved] What causes a java.lang.ArrayIndexOutOfBoundsException and how do I prevent it?

Your first port of call should be the documentation which explains it reasonably clearly: Thrown to indicate that an array has been accessed with an illegal index. The index is either negative or greater than or equal to the size of the array. So for example: int[] array = new int[5]; int boom = array[10]; … Read more

[Solved] Extract specific string from String [closed]

Use this String[] params = data.split(” “); String firstString = params[0]; split() function will split your whole string using space as delimiter, resulting in array of strings. First element of the array is the string you are looking for. 2 solved Extract specific string from String [closed]

[Solved] How can I convert my for loop into a recursive algorithm?

You do it by actually using the i parameter. private static final String ALPHABET = “abcdefghijklmnopqrstuvwxyz”; public static void binary(int n, String str, int i) { if (i == ALPHABET.length()) return; if (n == 0) { System.out.println(str); return; } binary(n – 1, str + ALPHABET.charAt(i), 0); // next letter starts at beginning of alphabet binary(n, … Read more