Your issues lies in your formatting and confusion between the use of the echo command and non PHP wrapped HTML. Code should read as follows when properly formatted. <?php $db_host = “localhost”; $db_username = “vistor”; $db_pass = “visitor”; $db_name =…
The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible…
Example SELECT * FROM tbl LIMIT 5,10; `# Retrieve rows 6-15` 5 – startIndex 10 – No of records from start index see here solved Explain this mysql query please? [closed]
I’m guessing you’re trying to find out if $catId is in the $result_2 array. If so, then you’ve already answered your question with your title here.. in_array if(in_array($catId,$result_2)) solved If in Array on PHP [closed]
you are saying that on change in four table you want to update the record in 5th table. For this purpose you can write an update trigger which will trigger on change on any one of the four tables and…
SELECT * from user, category WHERE user.id=[text field] or category.user_id=[text field] or category.cat_id=[text field] solved mysql Search data from multiple table
Introduction MySQL is a powerful and popular database management system used by many businesses and organizations. It is capable of storing and retrieving data from multiple tables, allowing for complex queries and data manipulation. In this tutorial, we will discuss…
Try this: SELECT amount – (amount * discount_percentage / 100) FROM tableA; 0 solved Mysql: How do I subtract a percentage from a number
Introduction Mysql is a powerful database management system that can be used to perform a variety of operations. One of the most common operations is subtracting a percentage from a number. This can be done using the MySQL SUBSTRING function.…
I would use the java.util.concurrent.* package since it’s newer and better for threading (which all timers/delay’s will need to implement in order to not block your program) This example will execute your task, then re-schedule itself automatically… nice! (the try/finally…
Logic is actually pretty simple here, you don’t want anything where the start and end are inside your period, or where they’re at opposite sides of any point in the range you’re looking for. SELECT R.roomID, R.name, R.facilities FROM –…
If you fix your syntax to select * from table1, table2; you will get a join where every condition is true, which is the same as the Cartesian product of the two tables. table1 table2 —— —— A 1 B…
Something like this should return the specified resultset: SELECT u.id AS user_id , u.user_name , SUM(a.user_id IS NOT NULL) AS total_count_of_articles FROM users u LEFT JOIN users_articles a ON a.user_id = u.id GROUP BY u.id, u.user_name ORDER BY total_count_of_articles DESC…
Issue(s) with your query: If you are giving an alias to a table use that alias for each reference. issue: FROM trans AS t1 WHERE (trans.Trans_date <= ‘2019-08-31’), here trans table is aliased as t1 and you are using again…
You can’t use not like directly in a show tables statement, but you could put it in a where clause: SHOW TABLES WHERE tables_in_db NOT LIKE ‘wp_2_%’; solved NOT LIKE not working with SHOW [duplicate]