You could use a comprehension(But you need to convert those numbers to string), Try code below: converted = {‘w’: 4, ‘a’: 3, ‘d’: 1, ‘e’: 1, ‘x’: 6} print(“”.join([str(char) for k, v in converted.items() for char in (k, v)])) solved Join Operation for Dictionary in Python [closed]
Try the following approach #include <stdio.h> #include <string.h> int main(void) { enum Animal { cat, dog, elephant }; char * animal_name[] = { “cat”, “dog”, “elephant” }; enum Animal b; size_t n; char s[100]; fgets( s , sizeof( s ), stdin ); n = strlen( s ); if ( s[n – 1] == ‘\n’ ) … Read more
Well, if I am interpreting your question right, you can declare an array or list, then initialize these elements in a loop For example (array) (if you want a fix number of elements): int n = 10; // number of strings string[] str = new string[n]; // creates a string array of n elements for … Read more
In your code, int l= arr[0].length; in this line, arr[0] represents the value in array named as arr at 0th index. Hence length function can be used in this way to find the length of value stored in array at 0th index. int l = arr[0].length(); In order to find out the length of array, … Read more
create a new member for your Activity like: int actual = 0; Then create a ‘next’ button: nextButton = (Button) findViewById(…); nextButton.setOnClickListener(new OnClickListener() { @Override public void onClick(View arg0) { actual = actual < countires.length – 1 ? actual + 1 : actual; String country = countires[actual]; btn1.setText(country); } }); Same goes for the previous … Read more
As per my understanding you are trying to assign space value in to char type .But the value you given is a string and trying to assign in to a char type .if u want to assign a space character do it by using ‘ ‘. char mychar=” “; //wont works because you are assigning … Read more
Since the pointer returned by malloc() is sufficiently well aligned to be used as a pointer to any type, you could (but probably shouldn’t) use: assert(sizeof(float) <= 10); void *data = malloc(10); char *str = data; strcpy(str, “123.4”); float *vp = data; *vp = strtof(str, NULL); …use *vp… free(data); And now you can use *vp … Read more
The first method you are calling is Read which returns one character. But it blocks until you hit the Enter key. From MSDN: The Read method blocks its return while you type input characters; it terminates when you press the Enter key. Then you call ReadLine which returns a line. When you hit the Enter … Read more
Because is a summer saturday and I’m happy, I’ve written a little code for you, but it’s incomplete. The only “prebuilt” function that the code uses is puts and I don’t see way to don’t use it. The code has two problems: The strings cannot be longer than 64 bytes. If they are longer the … Read more
You do not need a regex for this, because a greedy algorithm will do. You can match a string against a pattern in O(n+p), where n is the length of string and p is the length of pattern, by following a very simple strategy: for each character of the pattern, look for a matching character … Read more
On request, here is how I would do this myself: First, I want to create a function that performs this operation, so it can be reused every time we need to do this. I could have this function return or populate a TList<TWordRec>, but then it would be tiresome to work with it, because the … Read more
You should use r.nextInt(3); to get a number from the range 0-2. So, switch(r.nextInt(3)) { case 0: myVar = “a”; break; case 1: myVar = “b”; break; case 2: myVar = “c”; break; } 0 solved How do yo randomly assign a value to a variable? [closed]
Please look if this program can help you. It takes the two strings as arguments from the command line. #include <stdio.h> #include <stdlib.h> #include <string.h> int *substring(char *s, char *t) { int strlen1 = strlen(s); int strlen2 = strlen(t); int len = strlen1 < strlen2 ? strlen1 : strlen2; int i, j, k; int longest … Read more
Try using input.next(); instead of input.nextLine(); Because input.nextLine(); advances this scanner past the current line and returns the input that was skipped. so if your input was 20, +, and 24, your method calc would get 20,24,null. 2 solved i cant get my calculator to work
the array variable $atts does not contain ‘name,position’ etc thats why you are getting this error. check the data that is coming in the array $atts. Just replace $atts with @$atts problem solved. 3 solved How to fix “warning illegal string”?