You can try this:<[a-z\s]+id=[\’\”]mobile[\w]+[\’\”][\sa-zA-Z\d\’\=\;\:]*>([a-zA-Z\d\s]+)<[\/a-z\s]+> Anyway it will not match special chars or symbols. You can test and optimize it here: EDIT – Code example This could be the portion of code to extract the messages: var rgx = @”<[a-z\s]+id=[\’]mobile[\w]+[\’][\sa-zA-Z\d\s\’\=\;\:]*>([a-zA-Z\d\s]+)<[\/a-z\s]+>”;…
try this: <?php $q1 = “{Hello|Hi} sir.”; $q2 = “{How are you?|How are you doing?}”; $q = substr($q1, 1, strpos($q1,’}’)-1); $q_end = substr($q1, strpos($q1, ‘}’)+2); $parts = explode(‘|’,$q); echo “<select name=\”q1\”>\n”; foreach($parts as $part){ echo “\t<option value=\””.strtolower($part).”\”>$part</option>\n”; } echo “</select>\n”;…
If it really looks like this: <myid>1234</myid> …you can extract it like this: Matcher match = Pattern.compile(“<myid>(\d+)</myid>”).matcher(str); …and then use the matcher repeatedly, getting the value from the capture group. But there’s a reason everyone is telling you to use…
Try using RegEx.Split() using this pattern: (.*This is common text.*) Well, giving priority to RegEx over the string functions is always leads to a performance overhead. It would be great if you use: (UnTested but it will give you an…
If you are looking for a way to split a text into paragraphs with a particular string, then you have come to the right place. In this article, we will discuss how to use a simple method to split a…
Does this work properly for you? System.Text.RegularExpressions.Regex r = new System.Text.RegularExpressions.Regex(“<input name=\”authenticity_token\” type=\”hidden\” value=\”.*\” />”); MatchCollection matches = r.Matches(theusercp); foreach (Match itemcode in matches) { autcode = UrlEncode((itemcode.Value.Split(‘\”‘).GetValue(5))); } Perhaps you’ll also have to write var autcode and/or Server.UrlEncode. 8…
The simple answer: (?!^)\b[A-Z]\w* It matches any capitalized word that isn’t at the beginning of the line (checked using a negative look-ahead and a word boundary). See it here at regex101. But your requirements are sketchy… John and I are…
I’m not sure if there is a way to short-circuit the Regex engine that way. You can use the control verbs (*FAIL) to immediately fail a match or (*LIMIT_MATCH=x) to limit the number of matches you receive to a specific…
Connection reset.*?\\b([^ .]+\\.xls)\\b You can use this regex.Grab the group 1 or capture 1.See demo. 1 solved How to search a particular string in a file using pattern matcher in java
One approach would be to use the parse_str() and parse_url() functions. You can use this to separate the string information to find a certain parameter value. parse_str(parse_url($urlString, PHP_URL_QUERY), $array) All of the parameters would be stored in the $array variable.…
They’re pretty easy actually, it took me half an hour to learn the basics. Here’s your regex anyways: [a-zA-Z]{2}\d{3}[a-zA-Z0-9]{1} See it at work here. 8 solved Regex for userid validation [closed]
You may use explode() to get it. $word= “who’s’who”; $results= array(); $parts = explode (“‘”, $word); foreach ($parts as $part) $results[$part]++; You then may output like: foreach ($results as $word => $count) echo $word . ” = ” . $count.…
There is NO such number that is less than 1900 and greater than 2020. Assuming instead you meant a number in the range 1900 <= x <= 2020, you can use the following regex: ^(19[0-9][0-9]|20[01][0-9]|2020)$ Demo solved Regex for a…
Are you looking for s/x([0-9a-fA-F]{1,5})/ chr hex $1 /eg 3 solved Regex , regular expression [closed]
Shouldn’t the a* match with the a in the string? No, because * means a can match zero or more times, so the ” empty string also matches that expression. That leaves ‘ad’ after the initial empty string to match…