This answer is based on the assumption that you do proper handling of your pointers between the part where you allocate memory for 1 element each and where you try to reallocate the memory. This part // realloc to correct size for(int a = 0; a < word_nb; a++) { *(word_list + (word_nb-1)) = (char … Read more
No this is not valid how ever you can do following: String[] name=new String[]{“h”, “e”, “l”, “l”, “o”}; or String name=new String(new char[]{‘h’, ‘e’, ‘l’, ‘l’, ‘o’}); solved Can we declare the reference variable as String for the char array? [closed]
string aS = “ABCDEFGHI”; char ch=”C”; int idx = aS.IndexOf(ch); MessageBox.Show(string.Format(“{0} is in position {1} and between {2} and {3}”, ch.ToString(), idx + 1, aS[idx – 1], aS[idx + 1])); This wont handle if your character is at position zero and some other conditions, you’ll have to figure them out. 2 solved C# get position … Read more
You could try this. String nbr = input.nextLine(); int a=nbr.charAt(0)-‘0’; int b=nbr.charAt(1)-‘0’; int c=nbr.charAt(2)-‘0’; Also, you could use substring and parse the result Using Integer.parseInt int a=Integer.parseInt(nbr.substring(0,1)); //Contains the leftmost digit 2 solved How do I select the first, second, or third digit from a String containing three digits? [closed]
Use output.put(i); since it takes one character at a time. But you really want to skip the for-loop and just write the whole vector in one write: output.write(f.data(), f.size()); 2 solved Save an unsigned char vector one by one
In your conditional statement, you’re assigning space to s[ i ] (operator =). You want to compare them (operator ==). Try if (s[ i ] == ‘ ‘) s[ i ] = ‘ ‘ is always true because the result of an assignment is the value assigned (space). This value is implicitly converted to a … Read more
The idea is not that bad, the main errors are the mix-up of numerical digits and characters as shown in the comments. Also: if you use dynamic memory, than use dynamic memory. If you only want to use a fixed small amount you should use the stack instead, e.g.: c[100], but that came up in … Read more
In the following, I use the term “character” to denote something that can be displayed on a screen and printed on paper by a computer. The official name in Unicode is “code-point”. The letter ‘a’ is a code-point – it is “character” number 97 (0x61), so is a ‘ྦྷ’ (character 4007, 0xfa7) Unicode as such … Read more
Here char *firstName[50]; firstName is array of 50 character pointer, and if you want to store anything into each of these char pointer, you need to allocate memory for them. For e.g for (int counter = 0; counter < 10; counter ++) { firstName[counter] = malloc(SIZE_FIRST); /* memory allocated for firstName[counter], now you can store … Read more
You’re initializing the variable myChar as type char, but trying to fit a String inside. Java uses double quotes (“”) for Strings and single quotes (”) for chars. To fix this is simple: char myChar=”\u00A9″; The single quotes make ALL the difference! solved incompatible types required char found java.lang.string