It doesn’t look like you’re properly saving the results of your string split. x.split(” “); returns a String[] with each of the pieces that were separated by ” ” e.g. String x = “1 x 2″; String[] split = x.split(” “); split[0] == “1”; split[1] == “x”; split[2] == “2”; You could probably benefit from … Read more
Here is your program edited to suit your needs. Everything new is explained in the comments in the code: #include <stdio.h> #include <stdlib.h> // Don’t forget # before include! int main() { char ch = NULL; //character for storing ‘q’ or ‘c’ do{ int x = 0; int y = 0; int r = 0; … Read more
python 3 simple calculator , need assistance understanding subject and completing task, new to python and coding in general [closed] solved python 3 simple calculator , need assistance understanding subject and completing task, new to python and coding in general [closed]
A better approach is to use a while loop to collect input, and only exit the while loop after receiving valid data. num1 = 0 while num1 == 0: value = input(…. if ValidateInput(value): num1 = value num2 = 0 while num2 == 0: value = input(…. if ValidateInput(value): num2 = value # do other … Read more
Write this code in the click event of calculate button private void Calculate_Click(object sender, EventArgs e) { if (textBox1.Text != “” && textBox2.Text != “”) { int diff = (Convert.ToInt32(textBox1.Text) – Convert.ToInt32(textBox2.Text)); textBox3.Text = diff.ToString(); if (diff >= 0) { textBox3.ForeColor = Color.Green; } else textBox3.ForeColor = Color.Red; } else { MessageBox.Show(“PLZ Enter the balances”); … Read more
try this.. function run() { var birth = new Date(document.getElementById(“Ultra”).value); var curr = new Date(); var diff = curr.getTime() – birth.getTime(); document.getElementById(“srt”).value = Math.floor(diff / (1000 * 60 * 60 * 24 * 365.25)); } solved Age Calculator in Javascript [closed]
The solution was found on performing my calculation, where i realized the android OS automatically displays large numbers in exponential form. solved Android Calculator, How to display ridiculously large numbers in exponential form
You are reading the value from display1 twice, you forgot to change the reading of number2 to display2. Replace: number2 = Double.valueOf(display1.getText().toString()); with number2 = Double.valueOf(display2.getText().toString()); Your function would end up being: if(minu){ number1 = Double.valueOf(display1.getText().toString()); number2 = Double.valueOf(display2.getText().toString()); display1.setText(“”); display2.setText(“”); displaySymbol.setText(“”); answer = number1 – number2; display1.setText(Double.toString(answer)); } 0 solved Android: Division and subtraction … Read more
you are overriding findViewById, remove these lines from code on first screen/Java code (always paste code and stacktrace as text!) public void findViewById(int z1){ } as you see findViewById is always void… this method belongs to Activity and you shouldn’t mess with them. it work like a charm and will return you proper View. doc … Read more
check this and please don’t add pseudocode case “%”: textBox_Result.Text = (Double.Parse(textBox_Result.Text) * resultValue / 100.0).ToString(); 2 solved Switch statement in a C# calculator
IMMEDIATE PROBLEM You increment your index value before you use it; this means that on the final iteration, it’s 1 too large for the final operation. Switch the bottom two lines of your loop: index = 0 while index < 7: print(arr[index]) totalNum = int(num[index]) * arr[index] index += 1 Even better, this should be … Read more
In the Settings View it should be sufficient to change, since you have already given it a correct name of a rate, you should also make it a rate var tipRate = [5, 10, 15, 20, 25, 30] to var tipRate = [0.05, 0.10, 0.15, 0.20, 0.25, 0.30] You can also get rid of the … Read more
This should point you in the right direction. indexOf will return the position of the = character in the String. You must use this expression (+1) as the sole argument to the substring method. It would be best to assign this expression once to a String then perform your operations. String value = ansField.getText(); String … Read more
Try the Scanner class. Like this: import java.util.Scanner; public class New { public static void main(String[] args) { System.out.println(“Calculator”); Scanner scanner = new Scanner(System.in); System.out.println(“Enter Parameter “); System.out.print(“a : “); float a = scanner.nextFloat(); System.out.print(“+|-|*|/: “); String op = scanner.next(); System.out.print(“b : “); float b = scanner.nextFloat(); float c = 0; switch (op) { case … Read more
You should do html = parseInt(this.prevEq) + parseInt(html); and html = parseInt(this.prevEq) – parseInt(html); Instead of html = parseInt(html) + parseInt(this.prevEq); and html = parseInt(html) – parseInt(this.prevEq); The order is not a problem when you’re adding. It is when you’re subtracting. (a + b) == (b + a) but (a – b) != (b – … Read more