Use String.split: String[] kvPairs = “key1=value1;key2=value2;key3=value3”.split(“;”); This will give you an array kvPairs that contains these elements: key1=value1 key2=value2 key3=value3 Iterate over these and split them, too: for(String kvPair: kvPairs) { String[] kv = kvPair.split(“=”); String key = kv[0]; String value = kv[1]; // Now do with key whatever you want with key and value… … Read more
You do not need a regex for this, because a greedy algorithm will do. You can match a string against a pattern in O(n+p), where n is the length of string and p is the length of pattern, by following a very simple strategy: for each character of the pattern, look for a matching character … Read more
use: string sample = “1a2b3c4d”; MatchCollection matches = Regex.Matches(sample, @”\d”); List<string> matchesList = new List<string>(); foreach (Match match in matches) matchesList.Add(match.Value); matchesList.ForEach(Console.WriteLine); or use LINQ: List<string> matchesList2 = new List<string>(); matchesList2.AddRange( from Match match in matches select match.Value ); matchesList2.ForEach(Console.WriteLine); 6 solved c# should i use string with regex matchs or not
I haven’t tested the below code, But this should get you started. I have used the BoyerMoore implementation available here What the below code is doing: The goal is to search for a pattern in an input document. The BoyerMoore class is initialized in the setup method using the pattern set in the configuration. The … Read more
ECMAScript 6 introduced String.prototype.includes: const string = “foo”; const substring = “oo”; console.log(string.includes(substring)); // true includes doesn’t have Internet Explorer support, though. In ECMAScript 5 or older environments, use String.prototype.indexOf, which returns -1 when a substring cannot be found: var string = “foo”; var substring = “oo”; console.log(string.indexOf(substring) !== -1); // true 6 solved How to check whether … Read more