[ad_1] Simple way is iterate and compare it. like below, I hope it may solve your problem int[] a = {1,2,2,3,4,3,5,5,7}; String b = “”; int count=0; for(int i = 0; i<a.length;i++){ for(int j=0; j<a.length;j++){ if(a[i]==a[j]){ count++; } } if(count>1){ count=0; b = String.valueOf(a[i]); }else{ count = 0; } } System.out.println(“last duplicate value : ” … Read more
[ad_1] use itertools.product to get the tuples (you will have to filter out the same number twice), then use set intersections of the digits to see if they have any digits in common. import itertools numbers = [12, 23, 26, 54] [t for t in itertools.product(numbers, numbers) if set(str(t[0])) & set(str(t[1])) and t[0] != t[1]] … Read more
[ad_1] How about using the basic base 10 to any base conversion, modified for custom digits: func numberToCustomRadix(_ number: Int, alphabet: String) -> String { let base = alphabet.count var number = number var result = “” repeat { let idx = alphabet.index(alphabet.startIndex, offsetBy: number % base) result = [alphabet[idx]] + result number /= base … Read more
[ad_1] Your logic to print is fine, all you need to do is to wrap the code into a for loop and excute it from 1 to 100, e.g.: for(int zmienna = 0 ; zmienna <= 100 ; zmienna++){ if (zmienna % 5 == 0 && zmienna % 3 == 0) System.out.println(“FizzBizz”); else if (zmienna … Read more
[ad_1] This is a number guessing Python code ,but it stops after entering the first guessing number. Can you tell me where is the fault? [ad_2] solved This is a number guessing Python code ,but it stops after entering the first guessing number. Can you tell me where is the fault?
[ad_1] You want something like this: public static Pair FindClosest(IEnumerable<Pair> list, int value) { Pair closest = null; if (list != null && list.Count() > 0) { foreach (var pair in list) { if (value <= pair.Max) { closest = pair; break; } } if (closest == null) { closest = list.Last(); } } return … Read more
[ad_1] Have you tried calculating the length within the function rather than in the console log? This ensures that all of the logic is first completed within the function before it is returned in the console log. Your function expects the string name, but you are passing name.length function getNameLength(name){ return name.length; } console.log(getNameLength(‘John’)); console.log(getNameLength(‘Argentina!’)); … Read more
[ad_1] Check this out may it will help you. (function(){ var ConvertBase = function (num) { return { from : function (baseFrom) { return { to : function (baseTo) { return parseInt(num, baseFrom).toString(baseTo); } }; } }; }; // binary to decimal ConvertBase.bin2dec = function (num) { return ConvertBase(num).from(2).to(10); }; // binary to hexadecimal ConvertBase.bin2hex … Read more
[ad_1] You can do it that way. It works very nice. $str =array(); for($i=0;$i<10;$i++) { for($j=0;$j<10;$j++){ $str[]=$i; } $j=0; } echo implode($str,’,’); 2 [ad_2] solved Increment number php every next number
[ad_1] def consecutiveLetters(word): currentMaxCount = 1 maxChar=”” tempCount = 1 for i in range(0, len(word) – 2): if(word[i] == word[i+1]): tempCount += 1 if tempCount > currentMaxCount: currentMaxCount = tempCount maxChar = word[i] else: currentMaxCount = 1 return [maxChar,tempCount] result = consecutiveLetters(“TATAAAAAAATGACA”) print(“The max consecutive letter is “, result[0] , ” that appears “, result[1], … Read more
[ad_1] I would personally generate a string and keep adding random number values to the end, as most number types would not have as many digits as you would like. string Number = “0.”; Random rand = new Random(); for (int i = 0;i < 20;i++) { Number += rand.Next(0,10); } [ad_2] solved c# How … Read more
[ad_1] $(“#num”).on(“keyup”,function(){ if($(this).val()>5) alert(“The number entered is greater than 5″); }); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <input id=”num” type=”number” value=”click”/> 5 [ad_2] solved If number entered > 5 then show message using JQuery [closed]
[ad_1] The commenters are right. It doesn’t matter how long the list of numbers is. R can do the operation in one go. x <- c(25.01, 25.8, 25.4) x-15 [1] 10.01 10.80 10.40 If you do run into a situation with many wide-ranging numbers and need to literally keep what comes after the decimal and … Read more
[ad_1] your supposed to create an array of intigers and pass it to the average function, and need to pass the size(so that you know how many times to loop). In the loop in your Average function add all the values to a temporary value, then divide by the count input-ed to the function. //returns … Read more
[ad_1] try: sum(int(y) for y in var.split()) >> 20 1 [ad_2] solved How to add numbers inside a variable? [closed]