Simply comment out the line specifying validators for the email attribute, or remove it altogether: # app # validates :email, :presence => false, :email => false You’ll also need to make a slight modification to your users table. By default,…
here is the simple javascript code which will validate both email and phone number. <html> <head> <script src=””></script> <script> function ValidateEmail(mail) { var mailformat = /^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/; // if (/^\w+([\.-]?\w+)*@\w+([\.-]?\w+)*(\.\w{2,3})+$/.test(myForm.emailAddr.value)) if(mail.match(mailformat)) { alert(mail); return (true) } alert(“You have entered an invalid…
This is quite easy to o actually. Requirement #1 and #3 are the easiest. To test for whether a string contains two words and are separated by exactly one space, just use the split method. For requirement #2, test if…
You can test for input success with an if: if (cin >> ch) … To ask the user to enter input again, you’ll need a loop, and you also need to call cin.clear() to restore the stream’s state: cout <<…
(?> … ) is the syntax for an atomic grouping. And the syntax for look-ahead assertion is just (?! … ). Edit Try this regular expression instead: .*$(?<!-CONST) The .*$ will consume everything and the look-behind assertion will exclude those that…
After going through the Pandas documentation, found the way to validate the data. Let’s just say you have a custom validation function. def validate_rating(rating): “””” Description: validate if hotel rating is a digit between 0 to 5 Args: rating (str):…
$(“#num”).on(“keyup”,function(){ if($(this).val()>5) alert(“The number entered is greater than 5″); }); <script src=””></script> <input id=”num” type=”number” value=”click”/> 5 solved If number entered > 5 then show message using JQuery [closed]
Use the following code in your “keyup blur” event handler $(function() { $(‘input.alpha[$id=tb1]’.bind(‘keyup blur’, function() { if (this.value.search(/^[a-zA-Z]*$/) === -1) { alert(“Only valid characters present”); } }); }); Use + instead of * if you don’t want to allow empty…
You can use public bool IsAlpha(string strToCheck) { Regex objAlphaPattern=new Regex(“[^a-zA-Z]”); return !objAlphaPattern.IsMatch(strToCheck); } Regards solved Validate input string [closed]
You can convert it to String and then validate it with matches(). 2 solved Validating sql date type in java [closed]
Still not completly satisfied with the question but let me give it a shot. First let me point out that a default value is usually a single value. This value is usually set automatically when you add a new row…
I’m guessing that here we wish to validate these emails, for which we can use an expression similar to: ^([a-z0-9]+((?=\..+@.+\..+)[a-z0-9.]*@[a-z0-9]*\.[a-z0-9]*))$ with an i flag and we can allow more chars, if we like so. Demo RegEx Circuit jex.im visualizes regular…
The regexp would be: /^WI-(?:20[0-9]{2}|2100)-[1-9][0-9]{0,3}$/ This regexp allows arbitrary number of -nnn after the year: /^WI-(?:20[0-9]{2}|2100)(?:-\d+)+$/ 5 solved Regular expression to validate text field format “WI-XXXX-XXXX”
To meet your method name, you need this: protected bool IsStringAndNotNullAndEmpty(object value) { var s = value as string; return s == string.Empty; } Changing its name to IsEmptyString(object value) would be clearer though. It seems the OP actually wants…
I’d advise against stuff like this since there’s almost always a country where the phone numbers won’t match the validation, but here is the regex that matches your request ^\+?[0-9]{8,15}$ solved phone number validation in js [closed]