%e specifier is used to print value of float\double in exponential format. So here %1.4e will print 1 digit before the decimal point and 4 digits after the decimal point. So if bmax=12.242 then the output will be 1.2242e+01. 3 solved Correct printf formats for double numbers in C
You need simply enforce result string to show more zeroes if need. var a = 20.0f; a.ToString(“00.0000”, CultureInfo.InvariantCulture) //2 digits before and 4 digits after (.) Pay attention on fact that in your case the value may not be exactly 20.0, but something like 20.0012. In these cases you need to first convert it to … Read more
You can not cast double[] to an Double, because of the obvious reason that they are just not COMPATIBLE. If you are storing the double values in double[] and want to convert individual double to Double, you need not to typecast explicitly. Autoboxing works by default. double[] val = {1.01, 3.09}; for(Double d : val){ … Read more
This is how you can proceed: <script type=”text/javascript”> var timeleft = 30; var downloadTimer = setInterval(function(){ timeleft–; document.getElementById(“countdowntimer”).textContent = “:” + ((timeleft >= 10) ? timeleft : (“0” + timeleft)); if(timeleft <= 0){ clearInterval(downloadTimer); window.location.replace(“next_slide.html”); } },1000); </script> 0 solved Double digit 30 seconds countdown
I think you mean this.stack = new double[default_capacity]; and also this.stack = new double[capacity]; 4 solved Type mismatch: cannot convert from double to double[]
The culture on your machine probably does not consider the decimal seperator to be ‘.’ but ‘,’. Try with this: Convert.ToDouble(“168.255157”, CultureInfo.InvariantCulture); Edit: I confirmed that this was happening on my machine when I was using the wrong separator. This: Convert.ToDouble(“168,255157”, CultureInfo.InvariantCulture); also returned 168255157.0. You should always bear in mind the culture you are … Read more
I would personally generate a string and keep adding random number values to the end, as most number types would not have as many digits as you would like. string Number = “0.”; Random rand = new Random(); for (int i = 0;i < 20;i++) { Number += rand.Next(0,10); } solved c# How to generate … Read more
From Wikipedia: Short: Short signed integer type. Capable of containing at least the [−32,767, +32,767] range;[3][4] thus, it is at least 16 bits in size. The negative value is −32767 (not −32768) due to the one’s-complement and sign-magnitude representations allowed by the standard, though the two’s-complement representation is much more common. Double: Real floating-point type, … Read more
To answer your last point which is interesting (the other parts of the question are best answered by a debugger), a double that is too large for an int will cast into the largest possible int; similarly for a double that is too small for an int will cast to the smallest possible int. See … Read more
You can use functions std::stringstream from sstream or strtod from cstdlib or stod (If you are using C++11) as per your need. Quoting example from cplusplus.com // stod example #include <iostream> // std::cout #include <string> // std::string, std::stod int main () { std::string orbits (“365.24 29.53”); std::string::size_type sz; // alias of size_t double earth = … Read more
This expression (GUInumber1 >= 0 || <= 0) is not correct. You will need something on both sides of the <= operator. solved Strings in ternary operators interacting with numbers [closed]
#include <stdio.h> #include <string.h> typedef struct dbl9 { double array[9]; } Dbl9; Dbl9 fun(double *in){ Dbl9 ret; memcpy(ret.array, in, sizeof(ret.array));//There can be no assurance that <in> the correct return ret; } int main(){ double array[9] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0}; Dbl9 dbl9= fun(array); int i; for(i=0;i<9;++i){ printf(“%f\n”, dbl9.array[i]); } return … Read more
Just use String.format: System.out.println(String.format(“%.2f”,ans)); Note that this converts your value into a String, for calculations you should keep using its numeric representation. solved How to limit decimals digits?
By default, double.TryParse uses the following flags from NumberStyles: NumberStyles.AllowThousands NumberStyles.Float, which is an alias for the following combination: NumberStyles.AllowLeadingWhite NumberStyles.AllowTrailingWhite NumberStyles.AllowLeadingSign NumberStyles.AllowDecimalPoint NumberStyles.AllowExponent You can use the other overload of TryParse to specify only a subset of these to your liking. In particular, you want to remove (at least) the AllowExponent flag. 0 solved … Read more
You just need to print the number as a string. replace outputDegreesF() with public static void outputDegreesF(double degreesC) { double fahrenheit = 32.0 + (degreesC * 9.0 / 5.0); System.out.print(degreesC + ” ” + fahrenheit); // Easier // Or System.out.printf(“%.7f %.7f”, degreesC, fahrenheit); // Used more and lets you format } If you want to … Read more