Maybe this? <?php $num = ‘49.82’; $new_num = $num; $hundredth = substr($num, -1, 1); switch($hundredth) { case ‘0’: break; case ‘1’: $new_num = ($new_num – 0.01); break; case ‘2’: $new_num = ($new_num – 0.02); break; case ‘3’: $new_num = ($new_num – 0.03); break; case ‘4’: $new_num = ($new_num – 0.04); break; case ‘5’: break; case … Read more
decimal firstDecimal = 120.01M; double firstDouble = 120.01; float firstFloat = 120.01F; Console.WriteLine ((int)(firstDecimal * 100)); // 12001 Console.WriteLine ((int)(firstDouble * 100)); // 12001 Console.WriteLine ((int)(firstFloat * 100)); // 12001 Console.WriteLine (Convert.ToInt32(firstDecimal * 100)); // 12001 Console.WriteLine (Convert.ToInt32(firstDouble * 100)); // 12001 Console.WriteLine (Convert.ToInt32(firstFloat * 100)); // 12001 This means one thing…. you have something … Read more
Following is the program #include<stdio.h> main() { //float f = 233.1234; float f; float s; int x; int unit = 0; printf(“Enter the decimal number \n”); scanf(“%f”,&f); printf(“Entered the decimal number =%f\n”,f); s = f; while((int)s % 10) { s = s*10; } x = (int) s/10; printf(“x=%d,s=%f \n”,x,s); while(x % 10) { unit = … Read more
First, you need && operator instead of ||, Second, No need to use M. Looks like you are newbie, forgive me if you are not. min >= 0.01 && || <= 0.80 will be true if either min is bigger or equal to 0.01 or lesser or equal to 0.80, in this case min = … Read more
Nothing to stop this float fun(float a) { cout << fixed << setprecision(1); return a; } But that’s stupid code for a stupid puzzle. What does this have to do with real programming? 3 solved How to add decimal to floating point number with non-decimal value [closed]
The commenters are right. It doesn’t matter how long the list of numbers is. R can do the operation in one go. x <- c(25.01, 25.8, 25.4) x-15 [1] 10.01 10.80 10.40 If you do run into a situation with many wide-ranging numbers and need to literally keep what comes after the decimal and pick … Read more
The error is that %d in the format specifier of both scanf and printf represents decimal, so it expects an int (in the case of scanf, a pointer to int) Since you are declaring b and c as float, %d in the lines scanf(“%d”,&b); printf(“%d lbs is %d kgs.”,b,c); should be changed to %f respectively. … Read more
It is like below. bool Compare<T>(T x, T y) where T : class { … } So x and y should be of the same datatype. then only it can be compared. Decimal is 128 bits and single is 32 bits. Decimal is Decimal floating point and Double is Binary floating point. 2 solved == … Read more
That is double’s precision. You could use cookies = Math.round( cookies * 100.0 ) / 100.0; solved Java doesn’t know how to multiply? What? [duplicate]
Use Math.Ceiling() Convert.ToInt32(Math.Ceiling(26.0 / 12.0)); It rounds off the number to the next number. 1 solved How i can calculate Decimals to real integer?
How can validate data in excel so that we can throw an error if the decimal point of an input is less than “0.12”.ex: need to exclude 1.13 solved How can validate data in excel so that we can throw an error if the decimal point of an input is less than “0.12”.ex: need to … Read more
This should fix your problem (if I understand the problem, that is): var number = decimal.Parse(“0,55”.Replace(‘,’, ‘.’), CultureInfo.InvariantCulture); EDIT Not every culture uses the point (.) symbol as the decimal separator. If you don’t specify a format provider, the framework defaults to the current culture. I’m guessing that in this particular case, the decimal.Parse() method … Read more
Your code could be simplified a lot (and simpler code usually means that it’s simpler to find any mistakes). Here’s an outline of an easier way of doing this (I’ll leave it up to you to implement it in x86 assembly): void to_bin_string(unsigned input) { char output[33]; // The number of binary digits needed to … Read more
The answer was a simple Regex: bool regexmatch(string s){ regex e (“[-+]?([0-9]*\.[0-9]+|[0-9]+)”); if (regex_match (s,e)) return true; return false; } It will return true on integers (i.e. 56, -34) and floating point numbers (i.e. 6.78, -34.23, 0.6) as expected. 3 solved c++ Check if string is valid Integer or decimal (both negative and positive cases)
They seem to be HTML entities, but they are not complete, they should end with ‘;’ So the code should read: јυѕt The characters you see are: &#1112; CYRILLIC SMALL LETTER JE &#965; GREEK SMALL YPSILON &#1109; CYRILLIC SMALL LETTER DZE t a normal t In your browser it look almost like ‘just’ For a … Read more