Where did you come across the expression? It’s very likely that this is just to get you thinking about evaluations and booleans in R. Essentially, work inside of the parentheses and work outward until there is nothing left to evaluate. Let’s work through it step by step: ((111 >= 111) | !(TRUE)) & ((4 + … Read more
this solution, using itext, primefaces media. <p:dataTable widgetVar=”tb1″ id=”tablaFact” var=”item” selection=”#{listadoFacturasMB.selectedFactura}” selectionMode=”single” paginator=”true” rows=”20″ rowKey=”#{item.idFactura}” value=”#{listadoFacturasMB.facturaUtilList}”> <p:ajax event=”rowSelect” update=”:frm1:growl :frm1:dialog” oncomplete=”PF(‘servDialog’).show()” listener=”#{listadoFacturasMB.createPDF}”/> <f:facet name=”header”> <h:outputText value=”Listado de facturas (Cantidad: #{listadoFacturasMB.cantFact})”/> </f:facet> <p:column style=”width:10%” headerText=”Nro” sortBy=”noFactura” filterFunction=”#{utilMB.filterByName}” filterBy=”noFactura” filterMatchMode=”contains”> <h:outputText value=”#{item.noFactura}”/> </p:column> </p:dataTable> <p:dialog resizable=”false” closeOnEscape=”true” appendTo=”@(body)” modal=”true” id=”dialog” header=”Detalles de la factura” widgetVar=”servDialog” width=”1000px” height=”630px”> … Read more
I think this may be primarily opinion based. The way I see it, keeping things simple is sometimes the smarter way to design. To have the compiler accept some code that the compiler currently doesn’t accept, that would (at a minimum) require more complexity. The compiler would have the additional burden of determining which constructs … Read more
It has to do with operator sequencing. What the compiler thinks you’re doing is (a ? b = 3 : b) = 4 which obviously is incorrect. Instead, why not put the b on the left side, and get only the value to assign using the conditional expression, like b = a ? 3 : … Read more
How about: decoded = json.loads(myJson) which doesn’t give any errors when I run it. 0 solved extract json by Python [closed]
Yes every time you enter into the activity onCreate method is called. solved Pressing back button and current activity status
Your problem is clear here: max, mid and and min are uninitialized. Try: void swapy(double *x, double *y, double *z) { double max; double mid; double min; if( (*x>*y) && (*x>*z)) { max = *x; } else if((*y>*x) && (*y>*z)) { max = *y; } else { max = *z; } if((*x<*y) && (*x<*z)) { … Read more
The answer is pretty simple. And can be done can be done with a few tweaks in your code Your first for loop will produce an out of bounds error as in the 9th iteration (i = 8) you will be accessing a non existent arr[10]. Here is the corrected code: #include <iostream> using namespace … Read more
const result = [x,y,x][input – 1]; It’s an array that’s accessed by index. 2 solved How to use CONST when there are multiple conditions
Unless there is some indicator in your string of what kind of string it is, we may not be able to help. It looks too long for MD5 (34 instead of 32), but it could be MD5 and two characters of checksum. Some hashing algorithms work by applying a mix of algorithms, or the same … Read more
Your code does not compile. sender is Any, so you can’t access the property titleLabel directly. You either have to write: guard let senderedText = (sender as? UIButton)?.titleLabel?.text else { return } Or change the parameter type: @IBAction func inputformula(_ sender: UIButton) { As you can see, I inferred sender to be a UIButton because … Read more
you need to add a button to your .xml file like this : <Button android:layout_width=”match_parent” android:layout_height=”wrap_content” android:text=”Goal” android:layout_margin=”8dp” android:onClick=”add1ForTeamA” android:id=”@+id/Three_Button_B”/> then if you will notice that the android:onclick has been set to the add1ForTeamA method. Go to the mainActivity.java file and add this method `public void addOneForTeamA(View view) { scoreTeamA = scoreTeamA + 1; displayForTeamA(scoreTeamA); … Read more
There is a function combinations in itertools and it can be used to generate combinations. import random import itertools # Generate a random list of 30 numbers mylist = random.sample(range(-50,50), 30) combins = itertools.combinations(mylist, 3) interested = list(filter(lambda combin: sum(combin) == 0, combins)) print(interested) Note that the results from filter() and itertools.combinations() are iterables and … Read more
I’m guessing that tsidx and StreamDataBlockSize are Integer types. The largest number an Integer type can hold is 2,147,483,647. The multiplication in brackets is then done expecting an integer result, but the answer is out of the range of Integer types. Change your code to .. Dim position As Long = hisFileHeader.StreamStartDataPosition + (CLng(TSIdx) * … Read more
Presumably, you have more orders than you have employees. Hence, one employee is on many orders. When you run: select e.firstname from employees e inner join orders o on e.employeeid = o.employeeid; Then you are getting a list of all first names — so one employee name is going to be repeated, once per each … Read more