Here is how you would do it in Python 2: n = int(raw_input(“Type n:”)) total = 0 for i in range(1,n+1): total += i**2 print total Here is how you would do it in Python 3: n = int(input(“Type n:”)) total = 0 for i in range(1,n+1): total += i**2 print(total) This takes the numbers … Read more
<?php $sum1 = 0; $sum2 = 0; foreach($array[‘a’] AS $smallArray){ $sum1 += $smallArray[‘x’]; } foreach($array AS $smallArray){ $sum2 += $smallArray[‘h’][‘n’]; } solved find the sum of array value [closed]
Never use commas in the FROM clause. Always use proper, explicit JOIN syntax. Then, you cannot nest aggregation functions, so this should be sufficient: SELECT o.ID_DOSSIER, SUM(CASE WHEN ID_TYPE IN (‘0’, ‘1’) THEN TTL * -1 WHEN ID_TYPE IN (‘2’, ‘3’) THEN TTL END) FROM ope o JOIN actor a ON o.ID_ACTION = a.ID_ACTION GROUP … Read more
Sorting list items considering unit’s place. You can try: list1 = [1236,985,150,641876,167] sorted(list1, key=lambda n: n%10) [150, 985, 1236, 641876, 167] solved How to sort sum digits from the following list [closed]
For 1 to n the formula is sum =n(n+1)/2 , so from n1 to n2 you have to calculate sum of n1-1 terms snd sum of n2 terms and then subtract. sum_of_n1_to_n2 = n2(n2+1)/2 – (n1-1)((n1-1) +1)/2; 9 solved algorithm for the sum of integer peer from n to n [closed]
There are many statements in your code that literally DO NOTHING, 7+8+14; a+a2; b+b2; c+c2; d+d2; e+e2; f+f2; and answer=answer; You see, answer is uninitialized. You never set it’s value in the code, so you need something like // Initialize `answer’ here answer = 7 + 8 + 14; answer = answer + a + … Read more
there is a spelling mistake in your code of sum_positive in line (cout << sum_postive << endl;) – you have written sum_postive but you declared sum_positive. you are running a loop and taking input in the same variable number, so it will overwrite all the inputs and will store only the last value in variable … Read more
Here is an object version. This is not really what you’re after, but along the same lines and honestly, a bit neater as it’s a data structure. var myArray = [ “Apple: 10”, “Apple: 3”, “Banana: 3”, “Pear: 7”, “Pineapple: 7” ]; var newArray = {}; myArray.forEach(function(val) { var item = val.split(“:”); var key = … Read more
I echo the comment above. I believe StackOverflow is not a code writing service unless something changed very recently. However, let’s look at the code you posted. I think it would help to refactor this code into a more logical sense before attempting this in Javascript. That should make it easier to transpose. Every time … Read more
No need to bother with pandas. Text files are iterable. Just open it, operate on the line (string) and fill a dictionnary. file = “font.txt” with open(file, “r”) as f: dic = dict() for line in f: x = line.strip(“\n”).split(” “) key = int(x[0].strip(“px”)) value = int(x[1]) if key not in dic.keys(): dic[key] = [value] … Read more
Create a separate array then loop through the nested array and add them individually. If you cannot perform that then you shouldn’t be writing code in PHP 😉 solved array sum in array php [closed]
Because $product refers to each iteration of $output[“PriceInformation”][“PriceDetails”][“Price”], you can’t sum the entire array like this. The best way to do it would be to add it to a variable as you go: $your_sum = 0; foreach($output as $value) { $your_sum += $value[‘PriceInformation’][‘PriceDetails’][‘Price’]; } echo ‘Sum: ‘ . $your_sum; 1 solved Sum up array values … Read more
you should aggregate by column and then sum the results, try this: Notice that, the patient name should should have a numerical counter for keeping track. import pandas as pd import datetime import numpy as np # this a dummy set, you should have already this in your data frame dict_df = {‘Patient’: [1,2,3,4,5], ‘Positive’: … Read more
Use a total variable and add the generated number to the total import random x = 0 total = 0 while x<10: number = random.randrange(1,10) print(number) total += number x=x+1 print(total) 0 solved i’ve generated random numbers. Now i want to add all the numbers that are generated. What is the code to add them … Read more
Now that I understand that the list A itself is not going to change, but you expressed the idea of change meaning that the list has partitions where there are adjacent elements that are different, then a different solution comes to mind: Given your original data: A = [‘1′,’1′,’1′,’3′,’3′,’4’] B = [‘5′,’9′,’3′,’4′,’8′,’1’] We can use … Read more