If you for some reason can’t use imports, i.e. it is a homework to do it without, following is working version of your code: b = str(input()) k = b.split(‘.’) if (len(k)!=4): print(“input length is incorrect”) else: error = False for num in k: if int(num)<0 or int(num)>255: print(‘Error in your IP addr’) error = … Read more
import itertools as IT items = [‘Thu Apr 04’, ‘ Weigh In’, ‘Sat Apr 06’, ‘ Collect NIC’, ‘ Finish PTI Video’, ‘Wed Apr 10’, ‘ Serum uric acid test’, ‘Sat Apr 13’, ‘ 1:00pm’, ‘Get flag from dhariwal’, ‘Sun Apr 14’, ‘ Louis CK Oh My God’, ‘ 4:00pm’, ‘UPS Guy’] date_word = (‘Mon’, … Read more
You can get it working to some extent with pyenchant library that allows checking if a word is a valid word in a given language. Before checking linguistic validity, you need to check if the word is not empty and is more than one char long the word consists of letters only. So, in Python, … Read more
Your function doesn’t return anything. Printing is not the same thing as returning a value. The default return value for a function is None, which causes your error. You want to return something, most likely r.json(): def request(query, **params): query = (‘%27’+query+ ‘%27’) r = requests.get(URL % {‘query’: query}, auth=(”, API_KEY)) return r.json() then loop … Read more
Use self: class MyClass: def __init__(self): self.name=”John” def other_method(self): print(self.name) other_method will print “John”. solved Can you access attributes that were created with the init method from other methods in the class? [closed]
Django is a web framework. It allows you to create Web apps accessible via the Internet. Tkinter is a GUI framework. It allows you to create local applications on your device/ wherever the app is installed. solved Differences between if else in Django and Flask [closed]
In short: probably Matlab and Python achieve similar speeds in loops. The sources that you found are likely comparing old versions of Matlab, as @Eitan mentioned the new versions have proper Just In Time mechanisms which speed simple loops up a lot. There will be loops that python does faster, and those that Matlab does … Read more
The thing is that range and xrange are written in C, hence they are prone to overflows. You need to write your own number generator to surpass the limit of C long. def my_range(end): start = 0 while start < end: yield start start +=1 def conforms(k,s): k = k + 1 if s.find(“0” * … Read more
in your data ‘2,2’ is one string. But csv reader can deal with this: import csv result = [] with open(“data”, ‘r’) as f: r = csv.reader(f, delimiter=”,”) # next(r, None) # skip the headers for row in r: result.append(row) print(result) [[“‘1′”, “‘2′”, “‘3′”], [“‘1”, “1′”, “‘2”, “2′”, “‘3”, ‘3’]] 3 solved CSV IO python: … Read more
This can be environment issue of python. Kindly make sure you are in right environment and then install selenium pip install selenium solved How to import Selenium in Python [closed]
A lambda in Python is essentially an anonymous function with awkward restricted syntax; the warning is just saying that, given that you are assigning it straight to a variable – thus giving the lambda a name -, you could just use a def, which has clearer syntax and bakes the function name in the function … Read more
For your input, you can strip the character ‘ >>> s[0].strip(“‘”) ‘UIS006538’ >>> [i.strip(“‘”) for i in s] [‘UIS006538’] You can alternatively use an eval to get all such strings >>> [eval(i) for i in s] [‘UIS006538’] 1 solved python — Converting a string into python list 2
Try this: volumes = [“Volume:vol-XXXXXXXX”, “Volume:vol-YYYYYYYY”] json.dumps({ “volumes”: volumes }) solved Convert Python List to JSON Separate Objects [closed]
So there are several red flags right away… (multiple mainloop calls, classes in classes, calling root inside listbox) It seems like you are missing one of the main concepts of many gui frameworks, and that is that 1 window is not 1 application. In general the “root” of the application is the controller in the … Read more
Look at the data structure that you are getting back. It’s a dictionary that contains a list of dictionaries. You can access the list using the ‘results’ key: l = r.json()[‘results’] From there the dictionary containing the item you are after is the first item of the list, so: d = l[0] And the specific … Read more