When just a single result is needed, then no loop should be used. Just fetch the row right away. In case you need to fetch the entire row into associative array: $row = $result->fetch_assoc(); in case you need just a single value $row = $result->fetch_row(); $value = $row[0] ?? false; The last example will return … Read more
ok according to you comment and flowchart here is my suggestion to simplify it if (item.IsSet) { DialogResult isComplete = MessageBox.Show(“Complete set?”, “complete set?”, MessageBoxButtons.YesNo, MessageBoxIcon.Question); if (isComplete == DialogResult.No) // Break out } if(item.IsNew) { DialogResult goodQuality = MessageBox.Show(“Is the quality good”, “quality”, MessageBoxButtons.YesNo, MessageBoxIcon.Warning); if (goodQuality == DialogResult.No) //not accepted (break) } //if … Read more
You do it by actually using the i parameter. private static final String ALPHABET = “abcdefghijklmnopqrstuvwxyz”; public static void binary(int n, String str, int i) { if (i == ALPHABET.length()) return; if (n == 0) { System.out.println(str); return; } binary(n – 1, str + ALPHABET.charAt(i), 0); // next letter starts at beginning of alphabet binary(n, … Read more
To answer your second part of the question, with the assumption that every round the health will decrease till 1 player hits 0. (Because the way you are implementing it now, is that every time the inner For-loop is done, you reset the health of both wizard and sorceress, therefore making this requirement useless) Declare … Read more
A simple test proves the loop indeed works as intended: public static void main(String[] args) { int enemysno = 5; for (int i = 0; i < enemysno; i++) { System.out.println(“lalala ” + i); } } this works fine producing lalala 0 lalala 1 lalala 2 lalala 3 lalala 4 It was kind of obvious, … Read more
Introduction Recursion is a powerful tool in programming that can be used to solve complex problems. It is a technique that involves breaking down a problem into smaller sub-problems and then solving each sub-problem recursively. Converting a for loop into a recursive algorithm can be a great way to simplify code and make it more … Read more
Given an array of strings, convert each string into: uppercase if first letter is capital lower case if first letter is small solved Given an array of strings, convert each string into: uppercase if first letter is capital lower case if first letter is small
Where is the call for time() in your example? If you want to generate new time, means current time, you need to call time() function. for example: String currentTime=time(); … //some code … currentTime=time();//initializing current time 0 solved Return breakes loop
Introduction This article will discuss how to convert an array of strings into either uppercase or lowercase depending on the first letter of each string. We will go through the steps of writing a function that takes an array of strings as an argument and returns an array of strings with the first letter of … Read more
NSInteger index = 0; for(NSMutableDictionary *dict in arr_thisWeek){ NSLog(“%d”,[arr_thisWeek objectATIndex:index); index++; } But you already have the item at that index so you shouldn’t need it for array iteration. 0 solved Get the index value each for loop [closed]
Because count would reset to 0 on every iteration of the loop (also count would no longer be visible after the loop)! But, you don’t need count in the first place (since you have i and count is effectively i + 1 – and would be three after loop) – for (int i=0; i<5; i++) … Read more
You’re reusing the same string buffer. If you keep putting things into the same buffer without clearing it, you’re obviously going to get extraneous stuff from previous iterations. Simply declare the StringBuffer inside the while loop so that it is created on each iteration. Anyway, you should learn to use your debugger, instead of asking … Read more
Your while loop does not do the same thing as your for loop; the for loop starts at 1 and always increments i. Move the i += 1 before the even test: i = 0 while(i < 10): i += 1 if i % 2 == 0: continue print i because 0 % 2 == … Read more
Its because you’re using a list comprehension, instead you just have to have that replace function, like this… def printer_error(s): allowed = “abcdefghijklm” for char in s: if char not in allowed: s = s.replace(char, “”) return s print(printer_error(“xyzabcdef”)) 10 solved Why I can’t delete everything except for certain characters using a loop
Line 1 : Array Declaration.Line 2 : Then you run a loop for a half of the array.Line 3,4,5 : alternating the number like this shown below. Line 6 : Print it in the console window. solved How is it working? Please explain to me line by line [closed]