In both cases, when the program finishes, all the memory used is reclaimed. Memory leaks are most critical in programs which run for a very long time (days, weeks, months, years even). solved How long does memory leak itself exist in C++ and how does an equivalent Java program differ? [duplicate]
public void isSpace(String[] array) { for (int i=0; i<array.length; i++) { if( (array[i] == null) || (array[i].trim().length() == 0)) { //true on null, empty string, or white space only. Do something here array[i] = “add some thing here”; } else { //not null, not empty string, or not white space. Do something here } } … Read more
The linked list has references to all the objects it contains. In order to share the objects, you only need to pass a reference to the linked list. 2 solved Share objects in a linked list between many classes(java)
In order to connect to other computers in Java, you should use Sockets, and define your own Protocol (Basically, your protocol would consist on a handshake, and some way on asking the other part of the connection to send the text’s data). Anyways, I’d recommend you using a simple SQLite database To read and save … Read more
The first argument to replaceAll() expects a regex. The character | is a control character in regex. To make the regex parser understand that you “literally” mean |, you should pass \| to the regex parser. But \ is a control character in Java. To make Java understand that you mean to pass \| to … Read more
The part I’m trying to add You should be adding this part into the existing onCreate method, not the entire method body // Load an ad into the AdMob banner view. AdView adView = (AdView) findViewById(R.id.adView); AdRequest adRequest = new AdRequest.Builder() .setRequestAgent(“android_studio:ad_template”).build(); adView.loadAd(adRequest); // Toasts the test ad message on the screen. Remove this after … Read more
All possible code paths must return a value. In this case, if none of those if conditions are satisfied, nothing is being returned. You must have a final else that returns something. public static char Feld(){ if (vertical == 1 && horizontal == 1) { return Feld11 = Player1; } else if (vertical == 1 … Read more
Your code add one to the number passed as digit array. So when you add 1 to 123, you get 124. The code starts with the last digit, looks whether it is less than 9, then add 1 only to the last digit. this happens in the if-block. The return ends the function The code … Read more
The reason why you’re getting the same answer 5 times is because your do-while loop runs 5 times without changing the ‘creatures’ . System.out.println(a +” “+ b + ” ” + c + ” ” + d + ” ” +e); If you remove the do-while loop you’ll get the same answer only once however … Read more
Let’s say I have an array of characters (a string ) and I want to count how many time each character appears. However there should be no if solved Let’s say I have an array of characters (a string ) and I want to count how many time each character appears. However there should be … Read more
You can do it using nested loop, as you said in the question: public String[] randomArrayString(int length, int numberOfChar) { Random random = new Random(); char[] chars = “abcdefghijklmnopqrstuvwxyz”.toCharArray(); String[] array = new String[length]; String str; for (int i = 0; i < length; i++) { str = “”; for (int j = 0; j … Read more
private ArrayList<Student> readFile() throws FileNotFoundException { String fName = “p02-students.txt”; Scanner scan = new Scanner(new File(fName)); ArrayList<Student> studentList = new ArrayList<Student>(); while (scan.hasNext()) { String studentType = scan.next(); if (studentType.equals(“C”)) { studentList.add(readOnCampusStudent(scan)); } else { studentList.add(readOnlineStudent(scan)); } scan.nextLine(); } scan.close(); return studentList; } I didn’t get the error you mentioned earlier, but I was getting … Read more
When I understood the problem right then you can hold the last start number in a local variable: private int lastStartNumber = 0; private int getNextStartNumber(){ lastStartNumber = lastStartNumber + 1; return lastStartNumber; } 0 solved Give every new object a new attribute value (participants and start numbers)
This is one way (it does create two streams and does merge the two lines of code): Map<String, Long> map = Arrays.stream(“some text some spaces”.split(” “)) .collect(Collectors.groupingBy(Function.identity(), Collectors.counting())) .entrySet() .stream() .sorted(Map.Entry.<String, Long>comparingByValue().reversed()) .collect(Collectors.toMap(e -> e.getKey(), e -> e.getValue(), (v1, v2) -> v2, LinkedHashMap::new)); System.out.println(map); // This prints: {some=2, spaces=1, text=1} solved Word count in descending … Read more
You need to initialize marks array. int[] Math = {85,65,40,20}; int[] English = {35,55,68,75}; int[] ICT = {50,35,69,95}; int i; int x=1; int[] marks = new int[4]; if (x==1) { marks=Math; } else if (x==2) { marks=English; } else if (x==3) { marks=ICT; } for (i=0; i<4; i++ ) { System.out.print(marks[i] + ” “); } … Read more