[Solved] Word count in descending order using java lambdas

This is one way (it does create two streams and does merge the two lines of code): Map<String, Long> map = Arrays.stream(“some text some spaces”.split(” “)) .collect(Collectors.groupingBy(Function.identity(), Collectors.counting())) .entrySet() .stream() .sorted(Map.Entry.<String, Long>comparingByValue().reversed()) .collect(Collectors.toMap(e -> e.getKey(), e -> e.getValue(), (v1, v2) -> v2, LinkedHashMap::new)); System.out.println(map); // This prints: {some=2, spaces=1, text=1} solved Word count in descending … Read more

[Solved] Qualtrics Word Counter Javascript [closed]

Add an element with an id of ‘wordCount’ to the question text(in html editing mode) like this. <div id=”wordCount” style=”text-align: center; font-size: 2em; font-weight: bold;”>0</div> Then in the question’s Javascript input the following: Qualtrics.SurveyEngine.addOnload(function() { $$(‘.InputText’)[0].observe(‘keypress’, keypressHandler); function keypressHandler (event){ var entry = $$(‘.InputText’)[0].value.split(” “); var count = entry.length – 1; $(‘wordCount’).update(count); } }); This … Read more

[Solved] how do I count unique words of text files in specific directory with Python? [closed]

textfile=open(‘somefile.txt’,’r’) text_list=[line.split(‘ ‘) for line in textfile] unique_words=[word for word in text_list if word not in unique_words] print(len(unique_words)) That’s the general gist of it solved how do I count unique words of text files in specific directory with Python? [closed]

[Solved] For every possible pair of two unique words in the file, print out the count of occurrences of that pair [closed]

It seems inconceivable that the purpose of your assignment determining the frequency of word-pairs in a file would be to have you wrap a piped-string of shell utilities in a system call. What does that possibly teach you about C? That a system function exists that allows shell access? Well, it does, and you can, … Read more