[ad_1] You can do it as follows: String section = “PRIMARY”; Optional.ofNullable(student) .map( i -> (i.getStandard() > 5) ? “SECONDARY” : section ) .orElse(section); [ad_2] solved How to simplify if statement using Optional.ofNullable() [closed]
[ad_1] You may need to take a course on Java in general before you start jumping into Android which far more complex. Every argument for requestPermissions is not valid Java activity: this is not valid Java. Just use this. string[]{Manifest.permission.RECORD_AUDIO} is not valid Java. Change it to this new String[]{Manifest.permission.RECORD_AUDIO} requestCode.1 is not valid Java … Read more
[ad_1] Going by the comment discussion as well as the fact that you copied the code and didn’t write it yourself, I am guessing that you are trying to run that raw block of code by itself and didn’t realize that it must go in some other code. You must import the ArrayList and List. … Read more
[ad_1] Try this inside the loop with j as counter variable. This ensures that all the numbers from 2 to j-1 are not factors of j. Also check on other methods of prime number generation like Sieve of Eratosthenes, or reducing the complexity of this code by running loop till sqrt(j) counter=0; for(i=2;i<j;i++){ if(j%i==0){ counter=1; … Read more
[ad_1] Contract compliance for Java classes is checked statically by the compiler. Virtual machine is responsible for bytecode loading, verifying and running. It does not check whether some class implements all methods of some interface. 3 [ad_2] solved Why does Java allow you to create an object from a class that implements partially an interface … Read more
[ad_1] Angular have built in date pipe setDateTime(dateTime) { let pipe = new DatePipe(‘en-US’); const time = pipe.transform(dateTime, ‘mediumTime’, ‘UTC’); const date = pipe.transform(dateTime, ‘MM/dd/yyyy’, ‘UTC’); return date + ‘ ‘ + time; } html <span>{{dateTime| date:’MM/dd/yyyy’ : ‘UTC’}}</span> 1 [ad_2] solved how to convert Java Instant for showing Date in the angular client side? … Read more
[ad_1] Like Tobiel said if your data is stored in your database a query will be much better. However, if you need to do it in code you should modify your Collection sort. If in your scoreList you have a collection of Score objects you can compare their scores like this: Collections.sort(scoreList, new Comparator<Score>() { … Read more
[ad_1] You are experiencing SimpleDateFormat behaving as designed. It’s a behaviour that comes as a negative surprise to most. There are two solutions: the recommended one and the discouraged one. Recommended solution: LocalTime DateTimeFormatter timeFormat = DateTimeFormatter.ofPattern(“hh:mm a”, Locale.ROOT); try { LocalTime lt = LocalTime.parse(startTime, timeFormat); startTime = lt.format(timeFormat); System.out.println(startTime); } catch (DateTimeParseException e) { … Read more
[ad_1] The length of the array should change when you remove elements. The arrayLen variable stores the length of the array, but doesn’t change when the array’s length shrinks. To change it, you should be able to just replace arrayLen with arrayList.size(), which will change when your remove elements 0 [ad_2] solved Arraylist java.lang.IndexOutOfBoundsException: Index … Read more
[ad_1] mShowAnswers.setText( marksObtained ); This line contains the bug. As you are setting text into the textview(mShowAnswers) and the marksObtained is integer value, what is happening is Android is taking this marksObtained integer value as @StringRes and is trying to get matching String Value from Strings.xml which is not found and hence the exception is … Read more
[ad_1] printElements takes a single parameter of type ArrayList<String>, but you’re trying to give it two arguments of type ArrayList. 3 [ad_2] solved Using “args” but method still not taking more than one array as parameter? [closed]
[ad_1] A simple way: String str = “Good Morning”; String subStr=str.substring(0,7); char[] arr = subStr.toCharArray(); Arrays.sort(arr); for(int i = arr.length – 1; i >= 0; i–) System.out.print(arr[i]); [ad_2] solved How can I take a part of a string and sort it in reverse alphabetical order? [duplicate]
[ad_1] Files#lines returns a stream of all the lines in the file. You could join these lines to a single string, and then split it according to the separator: String separator = “:”; // for example… String entireFile = Files.lines(Paths.get(“file.txt”)).collect(Collectors.joining()); String[] separated = entireFile.split(separator); [ad_2] solved How to read txt file and save as a … Read more
[ad_1] In general you can’t update a spreadsheet inline, or the API doesn’t work nicely anyway. But, this is how you can modify an existing spreadsheet and overwrite the old workbook with the changed workbook. import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.InputStream; import org.apache.poi.ss.usermodel.Cell; import org.apache.poi.ss.usermodel.Row; import org.apache.poi.ss.usermodel.Sheet; import org.apache.poi.ss.usermodel.Workbook; import org.apache.poi.ss.usermodel.WorkbookFactory; public class ModifySheet { … Read more
[ad_1] Integer.parseInt couldn’t do the job, unless you were happy to lose data. Think about what you’re asking for here. Try Long.parseLong(String) or new BigInteger(String) for really big integers. [ad_2] solved In Java, how do I parse a string bigger than int size