You would use an Anonymous Inner Class, as Java 8 lambda expressions are essentially syntatical sugar which do nearly the same thing. That would look something like this. files.addAll(Arrays.asList(folder.listFiles(new FileFilter(){ @Override public boolean accept(File f) { return f.getName().endsWith(CustomConstantsRepository.FILE_EXT_DAT) && f.getName().startsWith(fileName))); } }))); solved File Lambda expression in Java 7
We see runtime performance issues compiling Java 6 bytecode with Java 7. Is that expected? No. It is not expected. It is possible … but I wouldn’t have predicted it, and I can’t think of an obvious explanation. What are the downsides/benefits of doing that? I can think of no real benefits to your problem … Read more
Files#lines returns a stream of all the lines in the file. You could join these lines to a single string, and then split it according to the separator: String separator = “:”; // for example… String entireFile = Files.lines(Paths.get(“file.txt”)).collect(Collectors.joining()); String[] separated = entireFile.split(separator); solved How to read txt file and save as a single string … Read more