You have to changes the format for working in both case: var isoDate = “2018-10-31” let dateFormatter = DateFormatter() dateFormatter.dateFormat = “yyyy-MM-dd” print(dateFormatter.date(from: isoDate)!) isoDate = “2016-04-14T10:44:00+0000” dateFormatter.dateFormat = “yyyy’-‘MM’-‘dd’T’HH’:’mm’:’ssZZZ” print(dateFormatter.date(from: isoDate)!) solved Format string to date format swift [closed]
If you output the Date object directly, its toString function is called implicitly, giving you a string in the format dow mon dd hh:mm:ss zzz yyyy, which may or may not be what you want. Using DateFormat implementation lets you…
Introduction DateFormat is an important tool for formatting and manipulating dates and times in Java. It is used to convert a date from one format to another, to parse a date from a string, to format a date into a…
using java 8 fluent Date/Time classes: LocalDate inputDate = … LocalDate prevSat = inputDate.with(TemporalAdjusters.previous(DayOfWeek.SATURDAY)); 4 solved How to get Saturday date from Calendar in java for a specified week? [closed]
Introduction If you are looking for a way to get the Saturday date from a Calendar in Java for a specified week, then you have come to the right place. In this article, we will discuss how to use the…
Try echo date(‘Y-m-d’, strtotime(‘Monday this week’)); echo date(‘Y-m-d’, strtotime(‘Sunday this week’)); 2 solved Week of the day for current date in php [closed]
The php date function can return a numeric representation of the day of the week. $current_date = (int)date(‘w’); Then you could walk through a loop outputing the remaining days. 1 solved Checking if the current date is greater than last…
The problem is that replace(“st”, “”) also removes the st ending of August, resulting in the input string seen in the error message. To handle this, you need to make sure the st suffix is right after a digit, so…
Try this: <?php $date1=date_create(“2013-03-15”); $date2=date_create(“2013-12-12”); $diff=date_diff($date1,$date2); echo $diff->format(“%R%a days”); ?> 1 solved Php date_diff inbuilt function example code [closed]
The LocalTime class represents a time of day, without any date component. That seems to be the class you want to use here. You can create LocalTime objects with LocalTime.of, and compare them with isBefore and isAfter. Like this. LocalTime…
You can try something like this: String str = “Saturday 17th March 2018”; DateFormat format = new SimpleDateFormat(“EEE dd MMM yyyy” , Locale.ENGLISH); System.out.println(format.parse(str.replaceAll(“(?<=\\d)(st|nd|rd|th)”, “”))); 1 solved Convert string date to date object Java [duplicate]
Well for hours and minutes (hh:mm) you can use this: var start = new Date(this.props.item.start); // this props returns Thu, 16 Feb 2017 08:00:00 GMT var dateStr = start.getHours() + ‘:’ + start.getMinutes(); 1 solved JavaScript convert date format [duplicate]
You didn’t set the timezone of the output date, so it’s defaulting to your systems’ timezone rather than UTC (which is what you were expecting). solved Parse ISO8601 in swift
Please try below i mentioned date format code,I hope it will help you, From this, String inputDate = “31.12.9999”; SimpleDateFormat dateFormatter = new SimpleDateFormat(“yyyy.MM.dd HH:mm:ss”); Date toDate = dateFormatter.parse(inputDate); To Change: Date date = new SimpleDateFormat(“dd.MM.yyyy”).parse(“31.12.9999”); String formattedDate = new…
I have updated the function… check now? navigator.geolocation.getCurrentPosition(function(position){ var long = position.coords.longitude; var lat = position.coords.latitude; var theDateC = new Date(); var D = (367*theDateC.getFullYear())-(parseInt((7/4)*(theDateC.getFullYear+parseInt((theDateC.getMonth()+9)/12))))+parseInt(275*(theDateC.getMonth()/9))+theDateC.getDate()-730531.5; var L = 280.461+0.9856474*D; var M = 357.528+0.9856003*D; var Lambda = L +1.915*Math.sin(M)+0.02*Math.sin(2*M); var Obliquity…