[Solved] Getting java.lang.ArrayIndexOutOfBoundsException, looked, cannot find an example thats the same

In your for loop, i correctly iterates from 0 to the maximum length. However you have code such as: tweetArray[i+1] … tweetArray[i+7] that will fail once i reaches (or gets close to) its maximum. That is, you are referencing past the end of the array. In general, if you need to check something about the … Read more

[Solved] how to add string array elements to arraylist in java

Your budgetEntityList is empty when you do budgetEntity= budgetEntityList.get(k); Doing a new ArrayList<>(capacity) does not fill your ArrayList with BudgetList objects, it only sets the initial capacity of your ArrayList. So, what you need to do is: for(int k=0; k < budgetEntityList.size() ; k++) { budgetEntity = new BudgetEntity(); budgetEntityList.add(budgetEntity); } And then, set the … Read more

[Solved] What does ArrayIndexOutOfBoundsException mean and how do I get rid of it? Here is a code sample that triggers the exception: [closed]

From inspection, I can see that your month array is missing the month of May, and therefore only has 11 elements in it. As a result, when you iterate over the 12 elements in the temperature array, you will get an array out of bounds exception during the final temperature, because there is no corresponding … Read more

[Solved] java.lang.ArrayIndexOutOfBoundsException when adding new elements to an array? [closed]

This works for me. public class PersonService { protected int lastItemInPersonArray = 0; private Person[] persons = new Person[100]; public void addPersonToPersonArray(Person personToAdd) { persons[lastItemInPersonArray++] = personToAdd; } public static void main(String[] args) { PersonService ps = new PersonService(); ps.addPersonToPersonArray(new Person(“P 1”)); ps.addPersonToPersonArray(new Person(“P 2”)); ps.addPersonToPersonArray(new Person(“P 3”)); System.out.println(ps.persons[0].nome); System.out.println(ps.persons[1].nome); System.out.println(ps.persons[2].nome); } } class Person{ … Read more

[Solved] I need a way around to tackle the following IndexOutOfBoundsException [closed]

The exception originates from my_data.get(position) in your onProgressChanged() listener. This listener is called asynchronously, when progress changes, but it refers to the original position provided, when you perform the onBindViewHolder(). So when at time X you do the onBindViewHolder(), position with value 2 is valid (if there are at least 3 entries in the list). … Read more

[Solved] java.lang.ArrayIndexOutOfBoundsException: length=6; index=6 | String.xml [duplicate]

Caused by: java.lang.ArrayIndexOutOfBoundsException: length=6; index=6 Means you are trying to access element at index 6 of an array with length 6. But arrays are 0-based indexed, meaning that the first element is in position 0 not 1. So the maximum index in a 6-element array is index 5. Your fault is probably in this line: … Read more

[Solved] Arraylist java.lang.IndexOutOfBoundsException: Index 3 out of bounds for length 3 Error

The length of the array should change when you remove elements. The arrayLen variable stores the length of the array, but doesn’t change when the array’s length shrinks. To change it, you should be able to just replace arrayLen with arrayList.size(), which will change when your remove elements 0 solved Arraylist java.lang.IndexOutOfBoundsException: Index 3 out … Read more

[Solved] How to solve ArrayIndexOutOfBoundsException error on trying to print appended object in an array? [duplicate]

This line System.out.println(ages[1].intValue()); is incorrect. ages is exactly one element. It should be System.out.println(ages[0].intValue()); with no other changes I get tony 50 70 To get 60, you would need to print the second element of oldAge. Like, System.out.println(oldAge[1]); solved How to solve ArrayIndexOutOfBoundsException error on trying to print appended object in an array? [duplicate]

[Solved] Reflection – Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: 0

Based on your exception, you aren’t passing any arguments to your class’ main method – System.out.println(Arrays.toString(args)); // <– to display your arguments. // Class<?> c = Class.forName(args[0]); // <– you should have a default Class<?> c = Class.forName(args.length > 0 ? args[0] : “java.lang.Object”); 3 solved Reflection – Exception in thread “main” java.lang.ArrayIndexOutOfBoundsException: 0

[Solved] pulling data from txt file getting java.lang.Arrayindexoutofboundsexception errors

so i figured out the fix to the ArrayIndexOutOfBounds errors and got it to work. The only remaining issue with the above programs is that answering question 4 (survivors by class). Here’s the code for that portion of the Titanic.java class that works: /** * Number of passengers who survived the sinking of the Titanic … Read more

[Solved] Error when accessing array – stack around the variable ‘scores’ was corrupted [closed]

It seems that this declaration: int scores[5]; Is incorrect. This creates an array with 5 numbers in it, indices from scores[0-4], however, you constantly refer to score[5], the sixth element of the array throughout your program. I recommend changing to int scores[6]; 2 solved Error when accessing array – stack around the variable ‘scores’ was … Read more