[ad_1] 1) A recursive solution has a few benefits. Generally it is more readable, and smaller in terms of lines of code. When it doesn’t work, it’s almost always harder to debug. It’s usually preferable when it runs faster than a non-recursive solution (see merge sort). 2) By definition. 3) True — the point of … Read more
[ad_1] The default return of the method will be None. If you perform the following: res = output() and print out res, it will be None. By default, None is always returned when not specifying a return. >>> def output(): … print “Hello, world!” … >>> res = output() Hello, world! >>> res >>> type(res) … Read more
Introduction [ad_1] This question is a duplicate of a previously asked question. This question is asking why a particular function returns a certain value. The answer to this question can be found by examining the code of the function and understanding the logic behind it. By understanding the logic behind the function, it is possible … Read more
[ad_1] You can’t access $dine in your second function because it’s nowhere defined. The $dine from your first function is only a local variable. I would suggest this solution which uses the fact that calculate_dinein_price() also returns the value of $dine: public function calculate_dinein_total(){ $total_dine = 0.00; $total_dine = $total_dine + $this->calculate_dinein_price(); return $total_dine; } … Read more
[ad_1] I would probably use a stopwatch – a timer would be difficult because i dont know of a way to reset the count back to 0 when a user clicks sucessfully. declare a stopwatch like so: Private maxWaitTimer As New Stopwatch then, perhaps a ‘game loop’ type of thing could be used in your … Read more
[ad_1] The time returning from a function should be negligible. Most processors have the instruction for returning from a function optimized, usually one instruction. If you are returning an object via copy, the return time depends on the time required to copy the object. Essentially, a return from function involves obtaining the return address, then … Read more
[ad_1] This is what I was looking for avgDelay <- function(carrier, dest) { TempTotal = 0 TempCount = 0 for(i in 1:dim(delays)[1]) { if(delays$CARRIER[i] == carrier & delays$ARR_DELAY[i] >0 & is.na(delays$ARR_DELAY[i]) == FALSE & delays$DEST[i] == dest) { TempTotal <-TempTotal + delays$ARR_DELAY[i] TempCount <-TempCount + 1 # keeps count of the number of delays } … Read more
[ad_1] I think you need something like this: // Make sure x is smaller than y if(x>y) { swap(&x, &y); } // Make sure x is smaller than z if(x>z) { swap(&x, &z); } // Now x is smaller than both y and z // Make sure y is smaller than z if(y>z) { swap(&y, … Read more
[ad_1] The second parameter of the setInterval function is the interval time in milliseconds – the 1000. Just change it to 750. var myTimer = setInterval(function() { console.log(“This will appear every 750 milliseconds”); }, 750); 1 [ad_2] solved How would I make a Timer which times things in 0.75 seconds Javascript?
[ad_1] You can’t use strcasecmp to compare characters. It’s not completely wrong, but a single character is not a properly terminated string. If you must do comparison this way, use strncasecmp: if(strncasecmp(&gender,&word_M, 1) == 0) That will limit it to comparing one character. Also, your retry loop doesn’t check for ‘F’, but checks ‘M’ twice. … Read more
[ad_1] For a start, here is the original ArregloBinario class with the spacing fixed up: package laboratorio9; import java.util.Random; import java.util.Arrays; public class ArregloBinario { private int[] datos; private static Random generador = new Random(); public ArregloBinario (int tamanio) { datos = new int[tamanio]; for (int i=0; i<tamanio; i++) datos[i] = 10 + generador.nextInt(90); Arrays.sort(datos); … Read more
[ad_1] Yes of course it is. How to make it happen depends on what these two files are (header files or main code files). Let’s call them function_defined.___ and function_used.___. There are two cases, depending on what each is. function_defined.hpp The simplest case — In function_defined.hpp, put int funct(int argument) {return 1} and in function_used.(c/h)pp, … Read more
[ad_1] The sane way to approach it would be to develop a 3rd party library and make it available over the internet through open source, Github etc. The GNU C dialect is one such example, which is a collection of non-standard compiler extensions used by the GCC compiler. One could join the GCC open source … Read more
[ad_1] The body of an if-statement can be either a compound statement, which is a list of statements surrounded by {}, or it is the single statement following the if‘s condition. That means that this code: if(n>=2) cout<<“number of times the function called: “<<endl; return n*factorial(n-1); is completely equivalent to: if(n>=2){ cout<<“number of times the … Read more
[ad_1] You can use pattern matching to determine which type of Array you’re dealing with. def arrTest[A](a :Array[A]) :Boolean = a match { case sa :Array[String] => sa.length < 2 || sa.sliding(2).forall(x => x(0) < x(1)) case ia :Array[Int] => ia.length > 2 && ia(0) == 1 && ia(1) == 1 && ia.sliding(3).forall(x => x(0) … Read more