If you’re going to do this with fscanf, you want to use a scan set conversion, like: int a, b; char c[256]; fscanf(infile, “%d %d %[^\n]”, &a, &b, c); To scan all the lines in the file, you’d do something like: while (3 == fscanf(infile, “%d %d %[^\n]”, &a, &b, c)) process(a, b, c); fscanf … Read more
Try removing ‘\n’ from the scanf, like this: scanf (“%i”,&x); Take a look at this discussion for additional info on using ‘\n’ in a scanf: Using “\n” in scanf() in C 2 solved C-Program – Taking extra entry to end program
You have declared string as a single character but you fill it with a string. This invokes undefined behavior. You should change your code to : char string [20] = “default”; //20 is random, you should use the maximum length of the input you may have printf(“The default String is: %19s”, string); scanf(“%s”, string); printf(“You … Read more
You can’t use strcasecmp to compare characters. It’s not completely wrong, but a single character is not a properly terminated string. If you must do comparison this way, use strncasecmp: if(strncasecmp(&gender,&word_M, 1) == 0) That will limit it to comparing one character. Also, your retry loop doesn’t check for ‘F’, but checks ‘M’ twice. solved … Read more
Check return value of scanf and clear input buffer in case of illegal input. Like this: #include <stdio.h> #include <stdbool.h> int main(void) { float sales, commission, earnings; int state; while(true) { printf( “Enter sales in dollars ( -1 to end ): ” ); if((state = scanf(“%f”, &sales )) != 1){ if(state == EOF) return 0; … Read more
Here char *firstName[50]; firstName is array of 50 character pointer, and if you want to store anything into each of these char pointer, you need to allocate memory for them. For e.g for (int counter = 0; counter < 10; counter ++) { firstName[counter] = malloc(SIZE_FIRST); /* memory allocated for firstName[counter], now you can store … Read more
I think this is what you are trying to do: int main() { int numList[5]; int i; for(i = 0; i < 5; i++) { printf(“Input number %d “,i); scanf(“%d”,&a[i]); } printf(“Your numbers: “); for(i = 0; i < 5; i++) { printf(“%d, “,a[i]); } printf(“\n”); } The method that I used for printing is … Read more
As said in remarks scanf(“%s%c”,a[i],&ch); try to read a ‘word’ as a string in a[i] and a char in ch Because a ‘word’ is ended by a separator and there is no space between %s and %c if a character is read to set ch that character is the first separator Example : #include <stdio.h> … Read more
From your tags, I’m guessing you’re using printf(). Simply leave out the “\n” character, which means “newline.”. In other words. printf(“> “); printf(“text\n”); This will print: > text 1 solved How do you type something on the same line of text in C [closed]
First off, you are obviously gonna get 1 due to the fact there is a problem in that scanf statement. You need to remove .2 from there as @weathervane has stated. cr = scanf(“%d %.2f”,&x,&y) to this: cr = scanf(“%d %f”,&x,&y) When you print cr, you will get a value of 2 instead of 1. … Read more
When the scanf(“%i”, &choice); statement is executed, it puts the integer entered by the user, into the int variable choice. However, it also leaves the newline character in the input buffer causing the user input to get thrown off. When the scanf(“%c\n”, &guess); statement is executed, the next character entered is placed on the input … Read more
I have modified your code. Please see the snipet code below #include <stdio.h> #include <conio.h> #define MAX 25 char welcomeMsg[]= “Please enter your name without ‘*’ or # ” ; char errorMsg[]= “\nError, please re-type your name. “; void main(void) { int j; char input; char name[MAX]; j=0; puts(welcomeMsg); do { input = getche(); if(input … Read more
The error is that %d in the format specifier of both scanf and printf represents decimal, so it expects an int (in the case of scanf, a pointer to int) Since you are declaring b and c as float, %d in the lines scanf(“%d”,&b); printf(“%d lbs is %d kgs.”,b,c); should be changed to %f respectively. … Read more
My main question is, are you using C or C++ ? The outcome and the appropriate/expected answer will be given with the right information. As you are talking about C++ also, I will put a sample code to manage this using the library provided in C++ (since C++11 onwards). Be warned than as I am … Read more
Here’s a working code: #include <stdio.h> int main () { char x[100] = {0}; char m; int i, j; printf (“Type:\n”); for (i=0; i<99; i++) { m = getchar(); getchar(); if ((m != ‘ ‘) && (m != ‘\n’)) { x[i] = m; } else { printf (“Breaking.”); break; } } printf (“\n”); for (j=0; … Read more