You can’t sort properties in an object. Copy the data into an array and sort it. Example: var arr = []; $.each(data, function(key, value){ arr.push({ id: key, data: value }); }); arr.sort(function(x,y){ var xn = x.data.userStatuINT; var yn = y.data.userStatuINT; return xn == yn ? 0 : xn < yn ? -1 : 1; }); … Read more
Try this :- #include <iostream> #include <math> using namespace std; int result, number, n; void function1(int number) { int result; result = pow(number,number); cout<<result; } int main() { for (n = 1; n < 10; n++) { function1(n); system(“pause”); } return 0; } 3 solved C++ program calculates n times n for the numbers 1 … Read more
$pages will be all immediate child divs of #main. If you have <div id=main> <div id=1> <div id=2></div> </div> <div id=3></div> <div id=4></div> <span id=5> <div id=6></div> </span> </div> Then $(‘#main > div’) will fetch 1, 3, and 4. If you did $(‘#main div’) then you’re finding all matching descendants, not just immediate ones, so … Read more
As direct answer, you should read file line by line, process them with Text::CSV, push new values to arrays with each array corresponds to original column and then just output them with join or like to get transposed representation of original. Disposing of each array right after join will help with memory problem too. Writing … Read more
add one more line in your function: mjob.clear(); private JsonParsingListener<JobList> mJsonListener = new JsonParsingListener<JobList>() { @Override public void onSuccess(JobList result) { if (null == mPagination) { mPagination = result.getPagination(); mPagination.setCurrentPage(0); if(null == result.getJobs() || 0 == result.getJobs().size()) { mMessageView.setText(getArguments().getString(ARG_EMPTY_MESSAGE)); mMessageView.setVisibility(View.VISIBLE); } else { mMessageView.setVisibility(View.GONE); } } else { mPagination.updateData(result.getPagination()); } if (null != mJobs) { … Read more
The first constructor: public Book(String bookname, String authorName) { mBookName = bookname; mAuthorName = authorName; mPageList = new ArrayList<>(); } Then you will have a new book without any page The second constructor: public Book(String bookname, String authorName, List<Page> pageList) { mBookName = bookname; mAuthorName = authorName; mPageList = pageList; } You will have a … Read more
Use Base64. It is widely used and probably already supported on your target framework. Just as base 10 allows only 10 possible glyphs within a character, base 64 allows 64 glyphs per characters. To express a 32 bit number such an an IP address, you would need at a base 64 number that has at … Read more
For pulse width modulation, you’d want to turn the LED off for a certain amount of time, then turn the LED on for a certain amount of time; where the amounts of time depend on how bright you want the LED to appear and the total period (“on time + off time”) is constant. In … Read more
You didn’t say exactly what errors you were getting, but you added some in-line comments. It’s best to post the exact error message separately from the code (and also indicate which line it came from, and what you expected that line to do). Looking at this one: if (a.leftLeft == b.leftLeft = 0){ there is … Read more
Although this question is very likely to get closed in the coming hours if you dont make your problem clearer, this might get you started at least: mydf <- scan(textConnection(“12376 167827 3454596 9676112 342102 1232103 546102 5645696 96767110 23423119 4577140 45435158 56767138 635435167 35443160 34534166 3213133 2132148 2342130 7656127 43234117 56545130 5645138 56455149”), ) plot(mydf, … Read more
Your if condition is not correct ! Your code should be : public static void main(String [] args){ BigInteger i = new BigInteger(“2”); double sqroot, cuberoot, fifthroot; while(true) { sqroot = Math.sqrt(i.floatValue()); cuberoot = Math.cbrt(i.floatValue()); fifthroot = Math.pow(i.floatValue(),1/5.0d); System.out.print(“i = “+i); if(Math.floor(sqroot)==sqroot && Math.floor(cuberoot)==cuberoot && Math.floor(fifthroot)==fifthroot){ break; } i= i.add(new BigInteger(“1”)); } System.out.println(i); } 1 … Read more
Yes, this is because the nodes are allocated dynamically. solved Nodes as a pointer
Search for = (Session\(“.*?”\))\.ToString and replace with = Cstr($1) It captures the Session(…) portion, which becomes the $1 replacement. solved Regex in Visual Studio 2013 [closed]
I can see how this would be misleading. However, a view does not “store” data (except for materialized views, which are a different store). A view is a query which is substituted into the query where it is used. Admittedly, it could be parsed in advance, saving a small amount of effort. However, a function … Read more
You need a method to get the name from the user. I presume you have that. And you need a folder within which to save the files (unless you want the user to specify folder as well). When users enter file names, they might type characters that are not allowed in file names. You must … Read more