Probably, you want to pass the arguments from the command line as follows: php /path/to/www/path/to/script.php arg1 arg2 In PHP script, you can access the variables as follows. <?php // $argv[0] is ‘/path/to/wwwpublic/path/to/script.php’ $argument1 = $argv[1]; $argument2 = $argv[2]; ?> Please let me know your thoughts. 1 solved how ca I get variable from ubuntu and … Read more
try: sum(int(y) for y in var.split()) >> 20 1 solved How to add numbers inside a variable? [closed]
You can use for for looping through array elements: var url = [“aaa”, “bbb”, “ccc”] for (var i = 0; i < url.length; i++) { if (window.location.href.indexOf(url[i]) > -1) { $(“#wrap”).css({display: ‘block’}); $(“#nav”).css({display: ‘block’}); break; } } 1 solved Declaring variables jQuery
Individual parameters aren’t iterable; you’d need a collection for that. Try changing it to an array instead: public void increment(int increment1, int increment2, int increment3) { int[] array = {increment1, increment2, increment3}; for(int i = 1; i < array.length; i++){ array[i] = 1; } } or public void increment(int[] increment) { for(int i = 1; … Read more
Just use the function itself to return the value. You do not need an additional output parameter. private static int runupdates(string arr) { updatestatement = “”; using (SqlConnection connection = new SqlConnection(SQLConnectionString)) { connection.Open(); using (SqlCommand command = new SqlCommand(updatestatement, connection)) { command.CommandText = updatestatement; int nummmm = command.ExecuteNonQuery(); connection.Close(); } } return nummmm; } … Read more
<?php echo (empty($LOGO) ? $TITLE : $LOGO) ?> will show $TITLE if $LOGO is empty. Otherwise will only show $LOGO. This operator is called the ternary operator. empty works like this: The following things are considered to be empty: – “” (an empty string) – 0 (0 as an integer) – 0.0 (0 as a … Read more
There’s two ways to do this: (1) a session, and (2) a form. A session is used to store values between page requests – it uses a cookie to identify your browser, which PHP manages for you. Your category could be set into a variable, and then re-read at page load. The other approach is … Read more
What you are asking for cannot be done this way. One way to handle this is to refactor the code, to break out the parts that are used in different parts in separate functions and then just call the parts needed, where needed. In this toy example this could be achieved as: def get_number(): number … Read more
first, read the file into a string line by line; then convert the string to a variable. In python, you can do the following i = 0 with open(“file.txt”, “r”) as ins: v = “var”+str(i) for line in ins: exec(v+”=’str(line)'”) i+=1 another approach is to read the lines into a list: with open(“file_name.txt”, “r”) as … Read more
Outside of the fact that you should probably be using an IDE to easily identify your mistakes…. Semi colon on main method, missing brackets, invalid variable types, etc. All you have is two arrays with one string value each. char stndCst[] = {“(sqftbrm + sqftdrm +sqfthal + sqftgrm + sqftstr)”/5}; char wtAvg[] = {“sqftbrm*bf” + … Read more
Try: $filename=”C:/xampp/project/Logs/” . $m . ‘.txt’; You had mismatched quotes. I’ve also changed the backslashes to forward slashes, because backslashes have special meaning in PHP strings; Windows allows either style to be used in pathnames. 4 solved PHP – use of variable [closed]
Jim’s answer would be the right way to go unless for any reason you can’t modify that code, otherwise: $.each(Analytic_Event, function(key, item) { // do whatever with item }); if you really have to anyways 1 solved Javascript: Can’t get an on-click event to search through an array
$_POST has value, after submitting form, so before that anybody can’t use $_POST .. <?php if(isset($_POST[‘title’])){ //Here in condition if(array_key_exists ( ‘title’ , $_POST )) can also be checked… //OR if(!empty($_POST)) OR if(!empty($_POST[‘title’])) can also be put.. $title = strip_tags($_POST[‘title’]); } ?> solved Error when writing code php [duplicate]
You want a variable lenght array, you can do it like this: int digit; scanf(“%d”, &digit); char test [digit+1]; This will work for your purposes. Usual restrictions of course apply. Keep in mind this functionality was only added in the C99 Standard. So if your compiler supports only previous standards, this will not work. However, … Read more
Remove the = in RemainHP. Right now it is equivalent to Health = Health – Injured; return Health; You want return Health – Injured 2 solved What’s wrong with my C# codes?