[Solved] Using returned outputs from one function in another in Python

I would rewrite the main function to be something like: def GetStudentInput(): score = 0 for i in range (4): print(“Mrs Pearson’s Class Test Score Data”) name = CheckStringInput(“What’s Your Name: “) score += CheckNumericInput(“What’s Your Score: “) print(score) This eliminates the need for an extra function and avoids using a list since you don’t … Read more

[Solved] Conditional summation in r

df <- data.frame(rep=c(0.2,0.3,0.2), lon=c(35,36,37), lat=c(-90,-91,-92), v1=c(10,0,8), v2=c(3,4,5), v3=c(9,20,4)) v <- as.vector(“numeric”) for(i in 1:3) v[i] <- sum(df$rep[df[,i+3]!=0]) solved Conditional summation in r

[Solved] in R, How to sum by flowing row in a data frame

We could use shift from data.table library(data.table) m1 <- na.omit(do.call(cbind, shift(df1$col1, 0:4, type=”lead”))) rowSums(m1*(1:5)[col(m1)]/5) #[1] 13.60 12.20 31.24 25.58 30.48 32.58 44.88 Or another option m1 <- embed(df1$col1,5) rowSums(m1*(5:1)[col(m1)]/5) #[1] 13.60 12.20 31.24 25.58 30.48 32.58 44.88 solved in R, How to sum by flowing row in a data frame

[Solved] function to calculate the sum of odd numbers in a given stack [closed]

just an example, you could pass your stack variable as an argument to the GetSum() function. private static int GetSum() { Stack<int> stack = new Stack<int>(); stack.Push(2); stack.Push(5); stack.Push(7); stack.Push(4); stack.Push(1); int sum = 0; foreach (int number in stack) { if (number % 2 != 0) { sum += number; } } return sum; … Read more

[Solved] How get the total sum of currency from a NSMutableArray [duplicate]

If the values are stored as NSNumber objects, you can use the collection operators. For example: NSArray *array = @[@1234.56, @2345.67]; NSNumber *sum = [array valueForKeyPath:@”@sum.self”]; If you want to format that sum nicely using NSNumberFormatter: NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; formatter.numberStyle = NSNumberFormatterDecimalStyle; NSString *result = [formatter stringFromNumber:sum]; NSLog(@”result = %@”, result); If … Read more

[Solved] Row-wise sum for select columns while ignoring NAs [closed]

Here is one way to accomplish this: #make a data frame df <- data.frame(a = c(1,2,3), b = c(1,NA,3), c = c(1,2,3)) #use rowSums on a dataframe made with each of your columns and specify na.rm = TRUE df$mySum <- rowSums(cbind(df$a,df$b), na.rm = TRUE) 0 solved Row-wise sum for select columns while ignoring NAs [closed]