You should try to do the complete code, but the base code is x = [[‘#’, ‘#’, ‘#’, ‘#’, ‘#’, ‘#’, ‘#’], [‘#’, ‘ ‘, ‘ ‘, ‘ ‘, ‘ ‘, ‘ ‘, ‘#’], [‘#’, ‘ ‘, ‘$’, ‘+’, ‘$’, ‘ ‘, ‘#’], [‘#’, ‘.’, ‘*’, ‘#’, ‘*’, ‘.’, ‘#’], [‘#’, ‘ ‘, ‘$’, ‘.’, … Read more
You need to cast the control to the type of your user control. If your class is really called Button then something like this var myButton = this.Controls[“button” + i] as Button; if(myButton != null && myButton.naz == “1”) … solved How get button Text from MyControl(Button)? [closed]
The Comparable interface is used to compare two objects and their order. As per the Javadocs, the compareTo method should return 0 if the two objects are equal, any negative number if this object is “smaller” than the specified other, and any positive number if this object is “larger” than the specified other. What “smaller” … Read more
type Set = Int => Boolean defines Set to mean a function from Int to Boolean. There is no ++ method on functions. That’s it. 0 solved Cannot resolve symbol ++ in Scala
Depending on the underlying implementation a remove in a List / Set can be O(1), O(n) or O(log n) (or some other even bigger complexity for esoteric implementations). ArrayList remove is O(n) on everything but the last element. Removing the last element in an ArrayList is O(1) (decrementing the size counter and setting the element … Read more
You can use the min and max functions set1 = {1, 2, 3, 5} set2 = {9, 8, 7, 10, 11, 12} x1 = len(set1) == max(set1)-min(set1)+1 # False x2 = len(set2) == max(set2)-min(set2)+1 # True 0 solved How do I write a function to check if a set is continuous? [closed]
If you have constant pool of Excersises, and you only need to access them by index, then you can use array instead: Excersise[] excersises = new Excersise[EXCERSIZE_SIZE]; //fill excersises //use excersises workout.add(excersises[index]); ArrayList is designed to have fast access to element by index, and it is using array underneath, but it has range check inside … Read more
Why isn’t std::set just called std::binary_tree? Because Tree doesn’t describe how the interface is used. Set does. std::set does not provide sufficient operations to be used as a general purpose search tree. It only provides an interface to a particular application of a search tree: The representation of a set. Technically the standard doesn’t specify … Read more
Aside from using loops explicitly, for List<Integer> list you can do: int sum = list.stream().mapToInt(Integer::intValue).sum(); If it’s an int[] arr then do: int sum = IntStream.of(arr).sum(); This is based on the use of streams. Or you can do this simple one liner loop: int sum = 0; for (Integer e : myList) sum += e; … Read more
Like this: import java.util.*; Set<Integer> a = new HashSet<Integer>(); a.add( 1); a.add( 2); a.add( 3); Or adding from an Array/ or multiple literals; wrap to a list, first. Integer[] array = new Integer[]{ 1, 4, 5}; Set<Integer> b = new HashSet<Integer>(); b.addAll( Arrays.asList( b)); // from an array variable b.addAll( Arrays.asList( 8, 9, 10)); // … Read more
Taken from a question here: Adding items to end of linked list class Node { Object data; Node next; Node(Object d,Node n) { data = d ; next = n ; } public static Node addLast(Node header, Object x) { // save the reference to the header so we can return it. Node ret = … Read more
SELECT Category, Tag1Value FROM table_name t1 WHERE EXISTS (SELECT 1 FROM table_name WHERE Tag2Value = t1.Tag1Value) UPDATE Try this : SELECT res.Category, res.tag, COUNT(res.tag) FROM (SELECT DISTINCT Category, Tag1Value tag FROM table_name UNION ALL SELECT DISTINCT Category, Tag2Value tag FROM table_name) res GROUP BY res.Category, res.tag HAVING COUNT(res.tag)>1 It return : category | tag ———————————– … Read more
You can use a sequence comprehension: let values = seq { for i in 1110 .. 10 .. 6660 do for j in 1 .. 6 do yield i + j } and create a set using Set.ofSeq e.g. let s = Set.ofSeq values 1 solved Creating Set in F# with elements from 1111 to … Read more
Here you go: @EDIT1: forgot that in python3.x print is a function. @EDIT2: this was not part of the original request. @EDIT3: formatted the output as later requested (I am not an expert in print formatting). @EDIT4: modified the output to match the modified request import string def func(str1, str2): s1 = set(str1) s2 = … Read more
Introduction Sets are a powerful tool in Python that can be used to find common letters between two strings. Sets are unordered collections of unique elements, meaning that each element can only appear once in a set. This makes them ideal for finding common letters between two strings, as each letter can only appear once … Read more