[Solved] How to sum some columns in a row [duplicate]
Use groupby df.groupby(“ID”)[“Cluster”].sum().reset_index() 1 solved How to sum some columns in a row [duplicate]
sum
[Solved] How to add indexes with a for loop from a multidimensional array using C#?
You need one more array, instead of four separate variables. This will make it easy to pick only (the right) one of the totals to update in the inner loop. Otherwise, all four scores will always get the score of the final golfer, since the inner loop currently sets all four variables. It will look … Read more
[Solved] Using returned outputs from one function in another in Python
I would rewrite the main function to be something like: def GetStudentInput(): score = 0 for i in range (4): print(“Mrs Pearson’s Class Test Score Data”) name = CheckStringInput(“What’s Your Name: “) score += CheckNumericInput(“What’s Your Score: “) print(score) This eliminates the need for an extra function and avoids using a list since you don’t … Read more
[Solved] Conditional summation in r
df <- data.frame(rep=c(0.2,0.3,0.2), lon=c(35,36,37), lat=c(-90,-91,-92), v1=c(10,0,8), v2=c(3,4,5), v3=c(9,20,4)) v <- as.vector(“numeric”) for(i in 1:3) v[i] <- sum(df$rep[df[,i+3]!=0]) solved Conditional summation in r
[Solved] Sum of the all the numbers between a and b [closed]
The code given looks OK, but if you want the sum without including the last number, as is generally the case you should change the for loop like this for(; index < endno; index ++) solved Sum of the all the numbers between a and b [closed]
[Solved] How to get sum of products of all combinations in an array in Python? [closed]
You can do with numpy and itertools: from numpy import linspace, prod from itertools import combinations arr = np.array([1,2,3,4]) [sum([prod(x) for x in combinations(arr,int(i))]) for i in linspace(1,len(arr), len(arr))] [10, 35, 50, 24] solved How to get sum of products of all combinations in an array in Python? [closed]
[Solved] How do you find the sum of all numbers in a set in Java? [duplicate]
Aside from using loops explicitly, for List<Integer> list you can do: int sum = list.stream().mapToInt(Integer::intValue).sum(); If it’s an int[] arr then do: int sum = IntStream.of(arr).sum(); This is based on the use of streams. Or you can do this simple one liner loop: int sum = 0; for (Integer e : myList) sum += e; … Read more
[Solved] How to sum and group values using MySQL ?
SELECT SUM(how_many) AS per_day, `date` FROM cigaretes GROUP BY DATE(`date`) 0 solved How to sum and group values using MySQL ?
[Solved] in R, How to sum by flowing row in a data frame
We could use shift from data.table library(data.table) m1 <- na.omit(do.call(cbind, shift(df1$col1, 0:4, type=”lead”))) rowSums(m1*(1:5)[col(m1)]/5) #[1] 13.60 12.20 31.24 25.58 30.48 32.58 44.88 Or another option m1 <- embed(df1$col1,5) rowSums(m1*(5:1)[col(m1)]/5) #[1] 13.60 12.20 31.24 25.58 30.48 32.58 44.88 solved in R, How to sum by flowing row in a data frame
[Solved] function to calculate the sum of odd numbers in a given stack [closed]
just an example, you could pass your stack variable as an argument to the GetSum() function. private static int GetSum() { Stack<int> stack = new Stack<int>(); stack.Push(2); stack.Push(5); stack.Push(7); stack.Push(4); stack.Push(1); int sum = 0; foreach (int number in stack) { if (number % 2 != 0) { sum += number; } } return sum; … Read more
[Solved] Sum of two numbers with function in haskell
I think you may be confusing type variables which are used in type annotations, and the actual values being passed to the function. In your definition of mygcd: mygcd c = a + b Unless a and b are defined elsewhere, this will be an error. In other words, these a, b, and c are … Read more
[Solved] How get the total sum of currency from a NSMutableArray [duplicate]
If the values are stored as NSNumber objects, you can use the collection operators. For example: NSArray *array = @[@1234.56, @2345.67]; NSNumber *sum = [array valueForKeyPath:@”@sum.self”]; If you want to format that sum nicely using NSNumberFormatter: NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init]; formatter.numberStyle = NSNumberFormatterDecimalStyle; NSString *result = [formatter stringFromNumber:sum]; NSLog(@”result = %@”, result); If … Read more
[Solved] Trouble adding and subtracting number from range [closed]
Don’t use any tricks in looping through your range. Just maintain a variable that tells you whether you should be adding this time, or subtracting, and alternate that variable with each pass through your loop. 3 solved Trouble adding and subtracting number from range [closed]
[Solved] Row-wise sum for select columns while ignoring NAs [closed]
Here is one way to accomplish this: #make a data frame df <- data.frame(a = c(1,2,3), b = c(1,NA,3), c = c(1,2,3)) #use rowSums on a dataframe made with each of your columns and specify na.rm = TRUE df$mySum <- rowSums(cbind(df$a,df$b), na.rm = TRUE) 0 solved Row-wise sum for select columns while ignoring NAs [closed]
[Solved] How to sum the digits of a number using Recursion [C]? [closed]
While @SamGrondahl is on the right track, unfortunately, if you enter a negative number it gives unexpected results. This should work properly with negative numbers: int sumdigits(int number) { int sign = number < 0 ? -1 : 1; number = sign * number; // abs the number if (number < 10) return sign * … Read more