strcmp & strncmp functions return 0 if strings are equal. You should do: if (strncmp(frase1, frase3, 4) == 0) … i.e.: char *str1 = “Example 1”; char *str2 = “Example 2”; char *str3 = “Some string”; char *str4 = “Example 1”; if (strncmp(str1, str2, 7) == 0) printf(“YES\n”); // “Example” <-> “Example” else printf(“NO\n”); if … Read more
For starters, you are trying to cast between an Object, String, and a primitive, int. This simply will not work. Objects cannot be cast to primitives, and vice-versa. A String, comprises of an array of char‘s wrapped into an Object. An int, comprises of a single signed decimal number. When you attempt to run a … Read more
just add a test : String firstWords = “”; if(splitVideoTitle.length>1){ firstWords = splitVideoTitle[0] + ” ” + splitVideoTitle[1]; } else firstWords=splitVideoTitle[0]; 0 solved Splitting a string caused ArrayIndexOutOfBoundsException [duplicate]
I could not post it to comment section. Please see below: List<Integer> integers = Arrays.asList(1, 2, 3, 4); int i = 0; StringBuilder sb = new StringBuilder(“[“); for (int value : integers) { sb.append((i == 0) ? “” : (i % 2 == 0 ? “,” : “:”)).append(value); i++; } sb.append(“]”); System.out.println(sb.toString()); Output is: [1:2,3:4] … Read more
In your conditional statement, you’re assigning space to s[ i ] (operator =). You want to compare them (operator ==). Try if (s[ i ] == ‘ ‘) s[ i ] = ‘ ‘ is always true because the result of an assignment is the value assigned (space). This value is implicitly converted to a … Read more
This question can be simply solved by using z-function in linear time. int NumberOfcopies(String t, String h){ // t = the first string i.e “ooo” // h = the second string i.e “wooooooooooooooooooooow” String s = t + “$” + h; // adding a sentinel character in between int n = s.length(); // length of … Read more
You should be able to just use string concatenation with +. mfile.open ( accname + “.txt”); If you are not on c++ 11, then you probably need a C-style string. mfile.open ( (accname + “.txt”).c_str()); 5 solved C++ Probllem with output [closed]
The idea is not that bad, the main errors are the mix-up of numerical digits and characters as shown in the comments. Also: if you use dynamic memory, than use dynamic memory. If you only want to use a fixed small amount you should use the stack instead, e.g.: c[100], but that came up in … Read more
Python strings are immutable. Any operation that appears to be changing a string’s length is actually returning a new string. Definately not your third option — a string can start out arbitrary long but can’t later change it’s length. Your option 1 sounds closest. You may find the Strings subsection of this web page helpful. … Read more
public static void main(String[] args) { List<String> data = new ArrayList<String>(); String yourRequiredString = “dessert”; data.add(“apple fruit”); data.add(“carrot vegetable”); data.add(“cake dessert”); for (int i = 0; i < data.size(); i++) { if (data.get(i).contains(yourRequiredString)) { System.out.println(i); } } } Hope this helps… solved Find String in ArrayList Containing Phrase
This is quite easy to o actually. Requirement #1 and #3 are the easiest. To test for whether a string contains two words and are separated by exactly one space, just use the split method. For requirement #2, test if the strings have a length that is larger than 2. Let’s say your string to … Read more
If you insist on regex, you can use positive look ahead as preg_replace(‘/,(?=}$)/’, ”, “helloworld,}”) // helloworld} Regex Explanation , Matches , (?=}$) positive look ahead. Checks if the , is followed by } and then end of line $ 7 solved How can I check if the last 2 characters of a string are … Read more
You need to check each case individually using the OR operator if you want to check more than one case. if (BothMods == “Yes” || BothMods == “YES” || BothMods == “yes”) { // do whatever } 4 solved c++ if specific words from string
So basically you to first split by – and then each side by a non-word character. Therefore you can try: String s = “ABC_DEF-HIJ (KL MNOP_QRS)”; String[] splits = s.split(“-“); // {“ABC_DEF”, “HIJ (KL MNOP_QRS)”} String[] lefts = split[0].split(“[^a-zA-Z]”); // {“ABC”, “DEF”} String[] rights = split[1].split(“[^a-zA-Z]”); // {“HIJ”, “”, “KL”, “MNOP”, “QRS”} String string1 = … Read more
Try this: string myStr= “46917 – Shampoo”; if (myStr.Contains(‘-‘)) { string[] tokens = myStr.Split(‘-‘); int i = Convert.ToInt32(tokens[0].Trim()); } solved Split string and convert to integer in C#