[Solved] How to return “” OR empty when value of float is 1

You have marked this as C++ (4-1i) should be shown as (4-i) You might find std::stringstream helpful. It simplifies the special handling for the imaginary part: virtual int foo() { std::cout << std::endl; show(4, -2); show(5, -1); return(0); } void show(int real, int imaginary) { std::stringstream ss; // default is blank if (-1 == imaginary) … Read more

[Solved] Please explain the output of this program based on pointers and strings?

Explanation line by line: Striker=Track; Sets Striker to point to the memory of Track, so Striker[0] would be equals to Track[0]. Track[1]+=30; Increases the value of the second index of Track by 30 (Track[1] = 50). cout<<“Striker >”<<*Striker<<endl; *Striker is the same as Striker[0], *Stirker+1 is the same as Striker[1] and so on. The output … Read more

[Solved] Explain Output in For loop C program [closed]

the condition here is implicit. C considers as true every integer not null. the ++i syntax is applied before the condition is evaluated Therefore the program run as follows: start: i=5 first loop condition (++i) => i=6 second loop iteration operation (i-=3) => i=3 condition (++i) => i=4 i is evaluated to true third loop … Read more

[Solved] C++ Probllem with output [closed]

You should be able to just use string concatenation with +. mfile.open ( accname + “.txt”); If you are not on c++ 11, then you probably need a C-style string. mfile.open ( (accname + “.txt”).c_str()); 5 solved C++ Probllem with output [closed]

[Solved] Memory issues in-memory dataframe. Best approach to write output?

I have been using the following snippet: library(data.table) filepaths <- list.files(dir) resultFilename <- “/path/to/resultFile.txt” for (i in 1:length(filepaths)) { content <- fread(filepaths, header = FALSE, sep = “,”) ### some manipulation for the content results <- content[1] fwrite(results, resultFilename, col.names = FALSE, quote = FALSE, append = TRUE) } finalData <- fread(resultFilename, header = FALSE, … Read more

[Solved] Why am I getting this output in C++? Explain the logic

NULL results in a false condition. You could imagine that NULL is a 0, so this: if(NULL) would be equivalent to this: if(0) thus your code would become: #include <stdio.h> #include <iostream> int main() { if(0) std::cout<<“hello”; else std::cout<<“world”; return 0; } where is obvious that because 0 results to false, the if condition is … Read more

[Solved] Why would the top print() statement print to the console after a later line of code

It’s because you are importing one before printing “top level two.py”. if one.py looks like this: print(“top level one.py”) def func(): #do something if __name__ == ‘__main__’: print(“one.py being run directly”) else: print(“one.py has been imported”) and with the two.py code above, then one.py is run first, when it is imported. Because one is running … Read more