You have marked this as C++ (4-1i) should be shown as (4-i) You might find std::stringstream helpful. It simplifies the special handling for the imaginary part: virtual int foo() { std::cout << std::endl; show(4, -2); show(5, -1); return(0); } void show(int real, int imaginary) { std::stringstream ss; // default is blank if (-1 == imaginary) … Read more
Explanation line by line: Striker=Track; Sets Striker to point to the memory of Track, so Striker[0] would be equals to Track[0]. Track[1]+=30; Increases the value of the second index of Track by 30 (Track[1] = 50). cout<<“Striker >”<<*Striker<<endl; *Striker is the same as Striker[0], *Stirker+1 is the same as Striker[1] and so on. The output … Read more
the condition here is implicit. C considers as true every integer not null. the ++i syntax is applied before the condition is evaluated Therefore the program run as follows: start: i=5 first loop condition (++i) => i=6 second loop iteration operation (i-=3) => i=3 condition (++i) => i=4 i is evaluated to true third loop … Read more
You should be able to just use string concatenation with +. mfile.open ( accname + “.txt”); If you are not on c++ 11, then you probably need a C-style string. mfile.open ( (accname + “.txt”).c_str()); 5 solved C++ Probllem with output [closed]
Try this one: counter = 0 while Amzn > 1000: counter+=1 print(“Watch”) Amzn = Amzn – (Amzn*.0103) else: print(“buy”) print(counter) 1 solved How can I count the outputs of a while loop in python? [duplicate]
You need to output spaces between the triangles: #include <iostream> using namespace std; int main() { const int size = 6; int uzunluk = size; for (int i = 0; i < size; i++) { for (int j = 0; j < uzunluk; j++) { cout << “*”; } for (int j = 0; j … Read more
There are many statements in your code that literally DO NOTHING, 7+8+14; a+a2; b+b2; c+c2; d+d2; e+e2; f+f2; and answer=answer; You see, answer is uninitialized. You never set it’s value in the code, so you need something like // Initialize `answer’ here answer = 7 + 8 + 14; answer = answer + a + … Read more
I have been using the following snippet: library(data.table) filepaths <- list.files(dir) resultFilename <- “/path/to/resultFile.txt” for (i in 1:length(filepaths)) { content <- fread(filepaths, header = FALSE, sep = “,”) ### some manipulation for the content results <- content[1] fwrite(results, resultFilename, col.names = FALSE, quote = FALSE, append = TRUE) } finalData <- fread(resultFilename, header = FALSE, … Read more
Use prompt like so: var number1 = parseInt(prompt(“Enter a number”)); var number2 = parseInt(prompt(“Enter another number”)); document.write(`${number1} + ${number2} = ${number1 + number2}<br>${number1} * ${number2} = ${number1 * number2}`); solved How to get user input and output it onto the web page [closed]
NULL results in a false condition. You could imagine that NULL is a 0, so this: if(NULL) would be equivalent to this: if(0) thus your code would become: #include <stdio.h> #include <iostream> int main() { if(0) std::cout<<“hello”; else std::cout<<“world”; return 0; } where is obvious that because 0 results to false, the if condition is … Read more
You can use the String.fromCharCode feature. For example: let myChar=”c”; let nextChar = String.fromCharCode(myChar.charCodeAt(0)+1); console.log(nextChar) // ‘d’ In your case, you would replace ‘c’ with your character variable. 0 solved Finding a faster way of checking characters in js [closed]
Here’s a brief table of how pointers map to normal (i.e. non-pointer variables) and vice versa (assume you’ve declared the pointer as int *varptr and your regular variable as int v): Dereferencing a pointer: *varptr v Passing the variable by reference: varptr &v Leave a comment if you have further questions and I’ll do my … Read more
It’s because you are importing one before printing “top level two.py”. if one.py looks like this: print(“top level one.py”) def func(): #do something if __name__ == ‘__main__’: print(“one.py being run directly”) else: print(“one.py has been imported”) and with the two.py code above, then one.py is run first, when it is imported. Because one is running … Read more
int q1 (int x[], int &y, int z). You pass a(pointer to the beginning of the array) to q1, so x is a in function q1. In this sense, changing x is changing a. y++. Every iteration, y gets 1 more. So? 8 solved How does c++ think when accessing a function with arrays? [closed]
If you use Java version 9 or higher, you can use the Java REPL (JShell) to try pieces of code. Install it on your computer, or use an online service (e.g. replit.com). Or, use a text editor, and create a .java file, compile it and run it: https://docs.oracle.com/javase/tutorial/getStarted/cupojava/win32.html 0 solved How to determine a java … Read more