[Solved] Split calculator expression with binary and unary operations [closed]

I found easy solution. You could just write it instead of complain that there is no code in the question. string expression;//my calculator expression string[] operators;//array that contains both unary and binary operators. for(int i=0;i<operators.length;i++) { expression = expression.replace(operators[i],” “+operators[i]+ ” “); } string[] Values= expression.split(” “); solved Split calculator expression with binary and unary … Read more

[Solved] Need some advice on split() method in Java [closed]

Guessing that you want to split by the comma then this will make it String toSplit = “LXI H, 2000H, MOV M A”; // this is a regular expression, you should study regular expressions too String[] split = toSplit.replace(“,”, “”).split(” +”); for (String s : split) System.out.println(s); Read the String class in the java API … Read more

[Solved] JavaScript Split array into multiple arrays inside [duplicate]

You could take an array of the wanted ids and an object which stores the index for the result set for a same group. var data = [{ candidateConfigId: “1”, value: “199128700790” }, { candidateConfigId: “2”, value: “Yujith” }, { candidateConfigId: “3”, value: “Male” }, { candidateConfigId: “4”, value: “SE” }, { candidateConfigId: “5”, value: … Read more

[Solved] Split a string C#

You can use Regex.Matches(): string source = “Mobile: +49 (123) 45678Telephone: +49 (234) 567890Fax: +49 (345) 34234234”; string[] phones = Regex .Matches(source, “[A-Za-z]+: \\+([0-9)( ])+”) .Cast<Match>() .Select(i => i.ToString()) .ToArray(); OR You can use IndexOf(): string source = “Mobile: +49 (123) 45678Telephone: +49 (234) 567890Fax: +49 (345) 34234234”; var telephoneIndex = source.IndexOf(“Telephone”, StringComparison.InvariantCulture); var faxIndex … Read more

[Solved] Split line from txt file

public static String[] SplitCsv(String value) { if (Object.ReferenceEquals(null, value)) return null; const Char quotation = ‘\”‘; const Char separator=”,”; List<String> result = new List<String>(); Boolean inQuotation = false; Boolean isStarted = false; StringBuilder Sb = new StringBuilder(); foreach (Char Ch in value) { if (inQuotation) { Sb.Append(Ch); inQuotation = Ch != quotation; continue; } if … Read more

[Solved] Using substring in line C# [closed]

It means that the values you are passing to Substring are not valid for the string they are being called on. For example: string s = “hello”; string x = s.Substring(0, 1); // <– This is fine (returns “h”) string y = s.Substring(1, 3); // <– Also fine (returns “ell”) string z = s.Substring(5, 3); … Read more

[Solved] Splitting a string ignoring whitespace

We’ll need to see your code before we can begin troubleshooting. However, the following code should work just fine: String address = “1,1,87 gandhi road,600005”; String[] stringArray = address.split(“,”); for(String str : stringArray) { // Do something with str. } 5 solved Splitting a string ignoring whitespace

[Solved] Split the number on a decimal

public static void main(String[] args) { String str = “154.232”; str = str.replaceAll(“\\..*”, “”); System.out.println(str); } or str.substring(0, str.indexOf(“.”)); or // check for index of . is not -1, then do following. str.split(“.”)[0]; output 154 solved Split the number on a decimal

[Solved] How to split an string array element by whitespace, and forming two new arrays?

As you mentioned the split-function can handle this. String[] types = new String[columnNameType.length]; String[] names = new String[columnNameType.length]; for(int i = 0 ; i< columnNameType.length; ++i){ names[i] = columnNameType[i].split(” “)[0]; types[i] = columnNameType[i].split(” “)[1]; } iterate your array and split every element on its own. 1 solved How to split an string array element by … Read more

[Solved] Splitting to words in a list of strings

A very minimal example: stops = {‘remove’, ‘these’, ‘words’} strings = [‘please do not remove these words’, ‘removal is not cool’, ‘please please these are the bees\’ knees’, ‘there are no stopwords here’] strings_cleaned = [‘ ‘.join(word for word in s.split() if word not in stops) for s in strings] Or you could do: strings_cleaned … Read more