Introduction Solution I think a cleaner answer uses the built-in enumerate and zip functions: Dlist = [17,13,10,6,2] Ilist = [5,9,10,15,18] def seqsearch(DS,IS): for idx, (d, s) in enumerate(zip(DS, IS)): if d == s: return f”Yes! Found at index = {idx}” return “No!\n-1” print(seqsearch(Dlist,Ilist)) It’s unclear whether you want to return just the first index, or … Read more
Test it in a console app. Remove things such as it being in run on the UI thread, and being run inside UI controls’ event handlers. Also, the act of displaying the message is huge overhead, so leave it out as it’s done in each method. All you really want to test is the performance … Read more
strcmp & strncmp functions return 0 if strings are equal. You should do: if (strncmp(frase1, frase3, 4) == 0) … i.e.: char *str1 = “Example 1”; char *str2 = “Example 2”; char *str3 = “Some string”; char *str4 = “Example 1”; if (strncmp(str1, str2, 7) == 0) printf(“YES\n”); // “Example” <-> “Example” else printf(“NO\n”); if … Read more
They check completely different things. is compares types. == compares values. var isString = “Abc” is String; // => true var equalToString = “Abc” == String; // Error: `string’ is a `type’ but a `variable’ was expected There is one domain where these can both apply, and have different meanings, and that’s in type checking: … Read more
The if condition checking must be done using == or === operator.Because = is used to assign something.So try this if($d == 2){ $dayznum = $dayznum2; } 3 solved PHP if($d=2) not working
You should write it like that, way easier to read : if (!Arrays.asList(ip, port, username, password).contains(newSet)) { saveButton.setEnabled(true); } else { saveButton.setEnabled(false); } Or : saveButton.setEnabled(!Arrays.asList(ip, port, username, password).contains(newSet)); 1 solved Java String comparison wrong outcome [closed]
Your code contains a lot of syntax errors. Please post actual code, I understand the issue you are talking about, that’s why I’m posting this answer. Please post questions with valid code, else you won’t get proper answer (Only get downvotes) Use the following code: NSArray *current = @[@”1″, @”6″, @”53″]; NSArray *newArr = @[@”1″, … Read more
I think this is what you’re looking for.. string a = “Beneficiation Return”; string b = “Return Beneficiation”; string c = “Beneficiation From Return”; string d = “Return From Beneficiation”; bool isSame = !a.Except(b).Any() && !b.Except(a).Any(); The bool isSame will return true because strings a & b contain the same characters. Compare a with c … Read more
You cannot compare strings using = (or even by ==, for that matter) operator. You need to use strcmp() for that. In your code, inside mobileno() function, if( s=”katrina” ) is essentially trying to assign the base address of the string literal “katrina” to s. It is nowhere near a comparison. That said, Never use … Read more
Yes, C++ has implicit casting from bool to int. However, I would suggest you make this a bit more clear that this is your actual intention, so that future readers understand your intent. Explicitly cast it to an int first. int var = 0; for (i = 0; i < 20; i++) { var += … Read more
I think it mainly depends on what you want to do in your application. If all you want to do is pushing some data and images (e.g. create a shop platform) i don’t see any reason, why ionic wouldn’t do the job and probably you’d see results a bit faster, as you don’t need to … Read more
Lets assume that set.seed(44) deaths<- 10:1 + sample.int(3, 10, replace = T) and spent<- seq(100, 550, by = 50 ) The very first thing you want to do when you get your data is literally to look at it. This can be done relatively painlessly with plot(spent, deaths) which yields So it looks like the … Read more
import Foundation let serverOutput = Data(“”” [ { “language”: “French”, “number”: “12” }, { “language”: “English”, “number”: “10” } ] “””.utf8) struct LangueUsers: Codable { let language: String let number: Int enum CodingKeys: CodingKey { case language case number } init(from decoder: Decoder) throws { let container = try decoder.container(keyedBy: CodingKeys.self) language = try container.decode(String.self, … Read more
java.lang.StringIndexOutOfBoundsException comes from this code: for (int i = 0; i < strLine1.length(); i++) { if (strLine1.charAt(i) != strLine2.charAt(i)) { System.out.println(“char not same at ” + i); } } When you scroll larger String strLine to an index, that is greater than the length of strLine2 (second file is smaller than the first) you get … Read more
Edit: Another version suggested by David Young is findIndicesIn xs ys = findIndices (`elem` ys) xs which I prefer to my solution below. If I understand correctly, you have two lists. Call them xs and ys. You want to find the index in xs of each element in ys. You don’t mention what you want … Read more