For the simplest case, you might solve this with a regular expression: >>> import re >>> re.sub(r”(‘?null’?)”, “‘Null'”, “{‘abcd’: null}”) “{‘abcd’: ‘Null’}” >>> re.sub(r”(‘?null’?)”, “‘Null'”, “{‘abcd’: ‘null’}”) “{‘abcd’: ‘Null’}” >>> but from the look of you example and the comment (which should really be part of your question) mentionning you might have a lot more … Read more
Your String result = “”; is null check it Your are returning null string change it You should return sb.toString(); instead of return result; EDIT public class PreDefinedAttributes { private Context mContext; private String mobile_os, mobile_model, mobile_brand, mobile_version, mobile_manufacturer; private String sdk_version, src, appname, appversion; private String lat = “”, lng = “”, device_id; private … Read more
try this, String s = “25999993654”; System.out.println(Character.getNumericValue(s.charAt(0)) + Character.getNumericValue(s.charAt(1))); 1 solved Can I product of charAt in Java? [duplicate]
The problem is that you are declaring your string array inside the loop and never populating it with anything. Move that string array outside the loop instead. Also, I don’t think you want to write the file every time through the loop, so move file write outside the loop too. static void Main(string[] args) { … Read more
You start by taking the string. ansible-playbook delete.yml –extra-vars “host=5.955.595 user=root pass=anotherpw vm=myVm” Then you escape all special characters. In this case, that’s just the 2 double-quotes. ansible-playbook delete.yml –extra-vars \”host=5.955.595 user=root pass=anotherpw vm=myVm\” Then you surround that with double-quotes, to make it a Java string literal. “ansible-playbook delete.yml –extra-vars \”host=5.955.595 user=root pass=anotherpw vm=myVm\”” Then … Read more
The point of single-quoted strings is that they don’t support escape characters. The documentation says this very clearly: All other instances of backslash will be treated as a literal backslash: this means that the other escape sequences you might be used to, such as \r or \n, will be output literally as specified rather than … Read more
Generate a random integer between 0 and (the array size – 1), both inclusive. Access your array with an index equal to this random number. We can’t give you ready-to-use code unless you show some efforts in terms of your own code. 2 solved How would I print a random array element? [closed]
You can just use the str.index(char, [beg, end]) method to retrieve the position of a character inside a string. The method allows you to add a beginning and end position that you can use to check for the different occurrences. Here the code: s=”CNCCN” dist = s.index(‘N’, s.index(‘N’) + 1) – s.index(‘N’) And its output: … Read more
A short and simple way is just to test the first and last characters: var input = // whatever var wrapped = input; if (‘”‘ === wrapped || !(‘”‘ === wrapped[0] && ‘”‘ === wrapped.slice(-1))) wrapped = ‘”‘ + wrapped + ‘”‘; (This works even on empty strings, because ”[0] is undefined and ”.slice(-1) is … Read more
Use CHAR_INDEX twice: SELECT *, SUBSTRING(path, pos1 + 1, pos2 – pos1 – 1) FROM tests CROSS APPLY (SELECT NULLIF(CHARINDEX(‘\’, path), 0)) AS ca1(pos1) CROSS APPLY (SELECT NULLIF(CHARINDEX(‘\’, path, pos1 + 1), 0)) AS ca2(pos2) — NULLIF is used to convert 0 value (character not found) to NULL Test on db<>fiddle 1 solved How to … Read more
Of course you can: #define S str##ing #define S_INCLUDE <S> #include <iostream> #include S_INCLUDE int main() { std::S str = “Hello world!”; std::cout << str << std::endl; } 2 solved Is there any way to use string in c++ without the word “string” appear in the program? [closed]
This seem to be an encoding issue, check the encoding of your source file. You should be able to change it with your IDE. To change encoding on eclipse, Window -> Preferences -> General -> Workspace : Text file encoding (Fetched from this post How to change default text file encoding in Eclipse?) 0 solved … Read more
The idea that “some compilers don’t work properly” is absurd. If you’re comparing C-style strings via char* pointers, then the =, !=, <=, … operators compare the pointers, not the strings they point to. In that case, use the strcmp() function instead. But since you’re asking about the compare function, you’re clearly not asking about … Read more
Your problem is evident in your debug output. getline does not strip the newline from the input, so for example you are searching for: “know\n” in “I do not know what to write\n” So your problem is not about stripping the \0 string terminator, but rather stripping the \n line-end. That can be achieved in … Read more
Indexes are zero-based: ↓ Peter Piper picked a peck of pickled pepper 111111111122222222223333333333444 0123456789012345678901234567890123456789012 ↑ The first p is at index 8. From the javadoc of indexOf(): Returns the index of the first occurrence of the character in the character sequence represented by this object, or -1 if the character does not occur. solved String.indexOf … Read more