Try this out. This should give you Exception. public static void main(String[] args) throws Exception { Scanner keyboard = new Scanner(System.in); System.out.print(“Enter: “); String entry = keyboard.nextLine(); keyboard.close(); if (entry.length() == 0) { throw new Exception(“Exception Found”); } else { String reverse = reverse(entry); if (reverse.length() == 0) { throw new Exception(“Exception Found”); } else … Read more
How about using the basic base 10 to any base conversion, modified for custom digits: func numberToCustomRadix(_ number: Int, alphabet: String) -> String { let base = alphabet.count var number = number var result = “” repeat { let idx = alphabet.index(alphabet.startIndex, offsetBy: number % base) result = [alphabet[idx]] + result number /= base } … Read more
#include <string> #include <iostream> // std::cout & std::cin using namespace std; int main () { string str (“This is an example phrase.”); string::iterator it; str.erase (10,8); cout << str << endl; // “This is an phrase.” it=str.begin()+9; str.erase (it); cout << str << endl; // “This is a phrase.” str.erase (str.begin()+5, str.end()-7); cout << str … Read more
First split the string. Then parse each element in String array to new array String[] s=str.split(“\\D+”); int[] intarray=new int[s.length]; for(int i=0;i<s.length;i++){ intarray[i]=Integer.parseInt(s[i]); } solved How to extract numbers from a String into an array
Well, you could try: Example 1: Using REGEX public static void main(String[] args) { String text = “Hello worlld this is someething cool!”; //add # between all double letters String processingOfText = text.replaceAll(“(\\w)\\1”, “$1#$1”); System.out.println(processingOfText); } Example 2: Using string manipulations public static void main(String[] args) { String text = “Hello worlld this is someething … Read more
This should work 🙂 String num1 = mEtfirst.getText().toString(); char[] temp = num1.toCharArray(); int i=0; num1=””; while(Character.isDigit(temp[i])) num1=num1+Character.toString(temp[i++]); This converts the string to a character array, checks the array character by character, and stores it in num1 until a non-digit character is encountered. Edit: Also, if you want to convert num1 to an integer, use: num1=Integer.parseInt(num1); … Read more
If it is about the longest possible matching (sub)string, thus the most specific one, the task actually can be solved pretty easy. sort the array descending by each of its string-item’s length property. Iterate the array … for each string item, try whether it is included within the given text. Stop iterating with the first … Read more
If the two strings are equal, there is no “uncommon subsequence”. If they are not equal, neither one is a subsequence of the other, but each one is a subsequence of itself, so each one is an “uncommon subsequence”. The longer of the two is the longest “uncommon subsequence”, and its length is the correct … Read more
Since this is homework, it would be a bad idea to write the code for you. So ideally, what you need to do, is get the words that fit into the criteria (that you mentioned) and store them in a list. Then take the length of the list. After that, you can divide the length … Read more
One thing you could do is extract all numbers, then use the second one: my $astring = “cool more 23423 random words of 1234 random other [wordssssssss] 23”; my @numbers = $astring =~ /[0-9]+/g; print “The second number is $numbers[1]\n”; 1 solved Take second of three numbers from a line in a file [closed]
res = [] for item in s.split(‘ ‘): … try: … int(item) … res.append(item) … except: … res += list(item) 5 solved How to separate string and integers to a list [closed]
String constant pool, new object initialization (with new keyword) versus normal initialization of a string? [closed] solved String constant pool, new object initialization (with new keyword) versus normal initialization of a string? [closed]
I just got a trick for you to achieving what you want. a = “hello world, hello there, hello python” a = a.replace(“hello”,”hi”,2).replace(“hi”,”hello”,1) print(a) So what exactly 2nd Line does it it is replacing first two occurrence of hello to hi and then replacing 1st occurrence of hi to hello. Thus getting the output you … Read more
Complete solution with regex : string source =”<img src=\”http://MyUrl.JPG.jpg\””; var reg = new Regex(“src=(?:\”|\’)?(?<imgSrc>[^>]*[^/].(?:jpg|bmp|gif|png))(?:\”|\’)?”); var match=reg.Match(source); if(match.Success) { var encod = match.Groups[“imgSrc”].Value; } solved Extract image URL in a string (RSS with syndicationfeed)
Ok here is the rewrite, the original code is better but this one might be easier to understand: #include <stdio.h> #include <string.h> int main() { char cur_char; char string[100]; int index = 0, count[255] = {0}; printf(“Enter a string\n”); gets(string); while (string[index] != ‘\0’) { char cur_char = string[index]; // cur_char is a char but … Read more