for loop can be simplifed to x= (pow(3,n)-1)/2 I have double checked this here:http://www.wolframalpha.com/input/?i=sum+pow%283%2Ci%29+for+i+from+0+to+%28n-1%29 3 solved Convert loop into mathematical equation
Ok here is the rewrite, the original code is better but this one might be easier to understand: #include <stdio.h> #include <string.h> int main() { char cur_char; char string[100]; int index = 0, count[255] = {0}; printf(“Enter a string\n”); gets(string); while (string[index] != ‘\0’) { char cur_char = string[index]; // cur_char is a char but … Read more
#include<stdio.h> #include<conio.h> int main() { int n=3,i,j,k,l,m; clrscr(); for(i=0;i<n;i++) { for(j=0;j<n-i-1;j++) printf(” “); for(k=0;k<=i-1;k++) printf(“*”,k+1); for(m=0;m<1;m++) { if(i<=0) printf(“*”); else printf(” “); } for(l=i-1;l>=0;l–) printf(“*”,l+1); printf(“\n”); } for(i=0;i<n-1;i++) { for(j=0;j<=i;j++) printf(” “); for(k=0;k<n-i-2;k++) printf(“*”,k+1); for(m=0;m<1;m++) { if(i==1) {} else printf(” “); } for(l=1;l>0;l–) printf(“*”,l+1); printf(“\n”); } getch(); return 0; } Finally I got my solution … Read more
Introduction Solved pattern programming is a type of programming that involves solving a problem by breaking it down into smaller, more manageable pieces. It is a powerful tool for problem solving and can be used to solve a wide variety of problems. Solved pattern programming is often used in computer science, engineering, and mathematics. It … Read more
You’re not updating the value of b inside the loop, so its value is always 6. You need to use an assignment operator to actually set a new value. So, use b = b + 3; or b += 3; instead. 1 solved Why is this while loop an infinite loop? High school introduction to … Read more
This line: if (mat1[i][j] == mat2[i][j]) is testing to see if the corresponding elements of the 2 matrices have the same value. Looking at it in context: if(mat1[i][j] == mat2[i][j]){ b = b & true; } else{ b = b &false; } is a rather cumbersome way of saying this: if(mat1[i][j] != mat2[i][j]){ b = … Read more
There are four basic functions that a search engine must perform: Gather a list of websites to crawl. Download the content of each of those web sites, and build up a mapping of “keywords” to pages. Allow users to type in keywords and then match those keywords against the mapping you built in step #2. … Read more
You may turn off short-circut evaluation in your compiler. If you work with your own types, you may overload || and &&. Overloaded logical operators are not short-circuted. Both things are really bad. Programmers expect logical operators to behave in certain way and are very likely to get super confused with this unexpected behavior. You … Read more
Hi all you have to do is replace that code with this $website_clean = str_replace(“http://”, “”, $values->Fields[7]->Value); $website_clean = str_replace(“https://”, “”, $website_clean); echo “<div class=”col-md-3 col-sm-12″> <h6>”.$values->Fields[0]->Value.”</h6> <p class=”bottom-hline”><i class=”fa fa-map-marker”></i> “.$address.”</p> <p class=”bottom-hline”><i class=”fa fa-phone”></i> <a href=”https://stackoverflow.com/questions/63148033/tel:”.$values->Fields[6]->Value.””>”.$values->Fields[6]->Value.”</a></p> <p class=”bottom-hline”><i class=”fa fa-globe”></i> <a href=””.$values->Fields[7]->Value.”” target=”_blank”>”.$website_clean.”</a></p> <p><i class=”fa fa-envelope”></i> <a href=”mailto:”.$values->Fields[8]->Value.””>”.$values->Fields[8]->Value.”</a></p> </div>”; if($cell_count == 4){ $cell_count … Read more
This answer will tell you how to do it, but will not give you the code. Writing the code is for you to do, since you chose at accept the challenge on CodingBat. More efficiently solution: Only iterate the array once. If current element is a 7, and previous element or the one before it … Read more
According to your list the Color rotates in a 10 years cycle and then has always 2 subsequent years with same color. Given that rule you can calculate an index in a field of year colors. #include <vector> #include <string> #include <iostream> using namespace std; int main() { const int base_year = 1984; vector<string> colors … Read more
I don’t know exactly what data structure you get the wall in, but assuming it is: std::vector<std::vector<char>> wall; To be able to perform melting using std::sort, it is best to have columns in the outer vector and rows in the inner vectors. // melting bricks for (int col = 0; col < wall.size(); ++col) //column … Read more
You can use reduce to create such function. function getMin(data) { return data.reduce(function(r, e, i) { let absR = Math.abs(r), absE = Math.abs(e); if (absR > absE || i == 0 || (absR == absE && e > r)) r = e return r }) } console.log(getMin([1.5, -1, 0, 5, 5.5, -4])) console.log(getMin([1.5, -1, 5, … Read more
All depend on the situation in hand. Both are valid but for multiple scenarios this one is quicker and much more efficient $a = $b == “” ? “default” : $b; solved Which is the most efficient way to work around the first one or the next one?
Your month comparisons are not correct. February is the 2nd month, not the 5th. As the second month, it doesn’t have 30 days (at least since I’ve been alive). You may want to swap those constants. 1 solved Usaco. Friday the thirteen. What is wrong with my code?