How to print a single statement as a whole statement in java without splitting it because of having multiple user values inside it? solved How to print a single statement as a whole statement in java without splitting it because of having multiple user values inside it?
If you look at the documentation of Pattern Boundary matchers $ The end of a line solved What is the use of the “$” in regex pattern? [duplicate]
You can add certain cache control headers to the HTTP request and/or response to prevent the use of cached copies. It’s also possible to suppress caching for an entire site, although this is generally ill-advised. See the spec for details about what to add. Specifically, you can add this header: cache-control: no-cache to the request … Read more
Most common way to do it: HashSet<ArrayList<String>> set = assingYourSet(); for (Iterator iterator = set.iterator(); iterator.hasNext();) { ArrayList<String> arrayList = (ArrayList<String>) iterator.next(); // Do Stuff… } 1 solved getting ArrayList from HashSet [closed]
The constructor executes in the following order: Calls the constructor of the superclass. Runs the instance initializer blocks in the order they were defined. Executes the rest of the body of the constructor. I.e., both of your sysout statements execute just before the assignment n=10;. That’s how it should be. See JLS §12.5. 1 solved … Read more
After considering your String It made me to add one thing String s2= “10 = On Battery “; String s[]=s2.split(“=”); int i=Integer.parseInt(s[0].trim());<———– use trim() otherwise you will have “10 ” with whitespace ^ But…… I have to split the numeric value 10 and words “On Battery”(Including the space in between them) String a=s2.split(“=”)[0];//”10 ” String … Read more
Here is the code that u can formulate to find a letter count from a text file.i have pushed an harcoded letter ‘a’ u can change it to dynamic also. import java.io.*; import java.util.Scanner; public class CountTheNumberOfAs { public static void main(String[] args)throws IOException { String fileName = “JavaIntro.txt”; String line = “”; Scanner scanner … Read more
You could stream the array, and filter using String::contains. String[] words = {“bad”, “bat”,”hat”}; String filter = “at”; List<String> list = Stream.of(words) .filter(word -> word.contains(filter)) .collect(Collectors.toList()); System.out.println(list); solved Java Array Searching [closed]
if you use SOAP do sth like this : String namespace = “http://tempuri.org/” ; String soapAction = “http://tempuri.org/MyMethod”; String methodName = “MyMethod”; String url = “http://192.168.1.2:8686/WebService/MyWebService.asmx” ; // my local or valid ip for webservice location SoapObject request = new SoapObject(namespace, methodName); // your webservice argument String username = “your username”; PropertyInfo usernameProp = new … Read more
Let’s take a closer look at your code’s conditional structure by correctly separating and using indentations: I like to add a bit of white-space to clearly know what’s going on. private void main(void){ //Indentation shows how program blocks are related to one another if (this.condition(parameters) == true) // Indentation here shows the following statement is … Read more
You try to parse a int 16905104155, but it is a long. Try to parse it as a long, Long.parseLong(serverUptimeText) 6 solved Integer.parseInt() saying “invalid int” in Marhsmallow 6.0.1, Its working perfectly in Pre-Marshamallow versions
String firstblock = “If debugging is thae process of removing software bugs, then programming must be the process of putting them in. Most good programmers do programming not because they expect to get paid or get adulation by the public, but because it is fun to program.”; byte[] bytes = firstblock.getBytes(); StringBuilder binary = new … Read more
Your both assumptions are wrong. 1) No one can disable browser back button (of course excluding the vendors :)). 2) Java plays on server side. Javascript plays on client side. You might want browser onunload function to prompt user. @Derek did a demo for what I mean : http://jsfiddle.net/DerekL/LZCj7/show/ 19 solved Is there any way … Read more
You’re mixing up && and ||, so your first if will never run as mentioned in the comments. So it looks like the only “Not Weird” print out is 2, 4 and even numbers > 20. So use this to your advantage to just check for the “Weird” outputs, otherwise print “Not Weird”. if (n … Read more
If you want to do task every 250ms even doStuff() may take more than 250ms, you should use a new thread to “doStuff”(In this case, more than one doStuff may work at a time) updated(I tried this in win7x64, JDK 1.6 and it works) java.util.TimerTask task = new java.util.TimerTask() { @Override public void run() { … Read more