[ad_1] This is how you would run a java program in a command line: java YourMainClass The command line arguments comes after that: java YourMainClass arg1 arg2 arg3 This would make the args string array contain “arg1”, “arg2” and “arg3”. If you make the args array an int[], how on earth is arg1 going to … Read more
[ad_1] About the fastest you can do this is to use String.indexOf: int pos = mymessage.indexOf(‘@’); String[] mysplit = {mymessage.substring(0, pos), mymessage.substring(pos+1)}; But I doubt it will be appreciably faster than: String[] mysplit = mymessage.split(“@”, 2); I suspect it might be slightly faster to use indexOf, because you’re not having to use the full regex … Read more
[ad_1] It looks to me like the 3.1 version is currently in beta, and the correct version number for the most recent beta is 3.1.0-beta1. Also, it appears that the maven artifacts are available on JCenter since 3.1.0-alpha2 (https://bintray.com/jmonkeyengine/org.jmonkeyengine/jme3-core/view). The private repository seems to no longer exist. Given that, I was able to get the … Read more
[ad_1] As far as cpu time – NO DIFFERENCE. The compiler will probably optimise them to exactly the same byte-code anyway. As far as technical debt is concerned – as soon as a real developer looks at this code and replaces it with: private static final String[] numbers = {“ZERO”, “ONE”, “TWO”}; private String getString(int … Read more
[ad_1] “(?s).*(ST\\*214|ST\\*210).*” In Java you need to enable DOTALL mode (to make . match with line terminators too). This can be done by including (?s) modifier. You had match only in this ST*214*900063730~ particular part of first string. 1 [ad_2] solved Looking for Correct Java REGEX for this kind of payload
[ad_1] The collections framework was designed to meet several goals, such as − The framework had to be high-performance. The implementations for the fundamental collections (dynamic arrays, linked lists, trees, and hashtables) were to be highly efficient. The framework had to allow different types of collections to work in a similar manner and with a … Read more
[ad_1] Create HashMap, put to this map all chars from first word with zero value. After that iterate over chars in second word and if this chars contains in map then increase map value for this char. Map<Character, Integer> map = new HashMap<>(); for(char c: word1.toCharArray()) { map.put(c, 0); } for(char c: word2.toCharArray()) { Integer … Read more
[ad_1] Let’s try to understand the code step by step. First of all, we call the function solution(), which is what leads to the execution of the puzzle answer. Solution funcion: public void solution() { int y = 0; b[0] = -1; while (y >= 0) { do { b[y]++; //if last cell was unsafe … Read more
[ad_1] Using for + range In python you can get a range by invoking range(begin, end) — where begin denotes the start of the range, and end is the upper limit (not included in the resulting range). Mathematically speaking the result will be the set of numbers in the range [begin, end). In order to … Read more
[ad_1] You have a small syntax error in that line of code. Instead of if (checkWin()); it should be if (checkWin()) Remove the ; [ad_2] solved Strange if statement always running even if conditions are not met [closed]
[ad_1] For Android you can use HTTP Connection URL. An example is mentioned here How to add parameters to HttpURLConnection using POST URL url = new URL(“http://yoururl.com”); HttpsURLConnection conn = (HttpsURLConnection) url.openConnection(); conn.setReadTimeout(10000); conn.setConnectTimeout(15000); conn.setRequestMethod(“POST”); conn.setDoInput(true); conn.setDoOutput(true); List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair(“name”, “Chatura”)); OutputStream os = conn.getOutputStream(); BufferedWriter writer = new BufferedWriter( new … Read more
[ad_1] BigInteger has the divideAndRemainder(…) method, one that returns a BigInteger array, the first item the division result, and the second, the remainder (which is what mod really does in Java). Update Including comment by Mark Dickinson to other answer: There’s a much simpler linear-time algorithm: set acc to 0, then for each digit d … Read more
[ad_1] A couple of things: First, your Java servlet is not really returning a “string”. When you write jsonArray.toString(), yes, you are turning the array into a string, but that is solely for the purpose of writing it across the network. HTTP is a text protocol. So, what the doGet method is actually returning, in … Read more
[ad_1] Apparently for solving your problem you need a list of all created instances for Person class. You should store that in a static variable, and then search on it. Something like this: final static allPeople List<Person> = new ArrayList<Person>(); Then you could search on that list with something like this: … if (allPeople.contains(aPerson)){ … … Read more
[ad_1] In overloading method resolution if the matched method with specific argument is not available the compiler won’t raise any error immediately, First it promotes the argument to the next level and check for matched method. 1)If the matched method is available then it will be considered and if it is not available then compiler … Read more