I don´t know if it could be for not having a “main” function Well, yes, that’s kind of a problem. Each program must have a main() function. Where else would the execution start from? how can i call the function “RegistrarUnaInclusion” to make it work? RegistrarUnaInclusion is a member function of class ListaCircular. Therefore, you … Read more
You haven’t actually provided code that exhibits your problem but, to answer your question, ways to pass argv[2] as a string to a function include #include <cstring> #include <iostream> void func(const char *s) { // treat s as a zero terminated string if (std::strcmp(s, “Hello”) == 0) { std::cout << “You said hello\n”; } } … Read more
You create new functions and call them from main: void foo() {} void goo() {} int main() { foo(); goo(); } There’s nothing technically wrong with having main1 or main2 methods, but there’s only one entry point of a valid C++ program, and that’s main. solved Guide to changing int main() [duplicate]
Foo has a static variable called Instance. This static variable is intialized before Main is executed, which causes the constructor Foo() to be called 1 solved why the program doesn’t begin with main method
System.exit(int) takes an integer argument, but otherwise you can call it to terminate your program. Why do you want to call your main() method again? It is normally the static entry point to your program. If there’s some code you wish to repeat, I’d suggest putting this in its own method and calling that (from … Read more
[Note: C does not have builtin string type. What C has is character array] This is a very easy to solve problem. Here’s the code given, it uses stdlib‘s builtin atoi function to convert string to int: #include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { if (argc == 2) { char *var_str = … Read more
Your first example uses a feature inherited from the outdated dialect of C which predated the first ANSI(1989) and ISO(1990) standard: namely, that you can write a function which doesn’t specify its return type, and in that case the type defaults to int. In early C, the void keyword and associated type did not exist. When … Read more
First of all, the declaration of main() is supposed to be int main(int argc, char **argv). You cannot modify that. Even if your code compiles, the system will call main() the way it is supposed to be called, with the first parameter being the number of parameters of your program (1 if no parameter is … Read more
Short Answer It’s boilerplate code that protects users from accidentally invoking the script when they didn’t intend to. Here are some common problems when the guard is omitted from a script: If you import the guardless script in another script (e.g. import my_script_without_a_name_eq_main_guard), then the latter script will trigger the former to run at import … Read more
Because it doesn’t make sense. Variables declared in a method are local to the method; i.e. they can’t be accessed outside the method. Why and how could these variables be modified outside the method? Code outside the method doesn’t even know of them, so you don’t need to protect them from outside code. solved Java … Read more
int arrayfirst[] [] ={{1,2,3},{2,3,4}}; int arraysecound[] [] ={{3,4,5},{6,7,8}}; here, arrayfirst and arraysecound contain two rows and three columns each (The number of inner curly braces separated by Comma signify number of rows, and the numbers written within these inner curly braces signify number of columns), so when you add their elements and try to store … Read more
This is how you would run a java program in a command line: java YourMainClass The command line arguments comes after that: java YourMainClass arg1 arg2 arg3 This would make the args string array contain “arg1”, “arg2” and “arg3”. If you make the args array an int[], how on earth is arg1 going to be … Read more
“Error: Main method not found in class nissan.lakshmi, please define the main method as:public static void main(String[] args) [duplicate] solved “Error: Main method not found in class nissan.lakshmi, please define the main method as:public static void main(String[] args) [duplicate]
You use post increment and decrement operator : return number++; return number–; For example here : public static int addOne(int number) { return ++number; } The value number is incremented but only as soon as the next statement. So as you return, the same value as the parameter is returned. It is the same thing … Read more
If you want the size() method to resize your window you need a least to declare one. I suggest you replace void setup(){ size(500,500); } with void setup(){ JFrame myFrame = new JFrame(); myFrame.setSize(500,500); myFrame.setVisible(true); } 2 solved size() command not working when containing method is run within a static method [closed]