[Solved] Android cursor out of bounds exception

[ad_1] Replace your below code cursor.moveToFirst(); Note newNote=cursorToNote(cursor); cursor.close(); return newNote; With if (cursor != null && cursor.moveToFirst()) { Note newNote=cursorToNote(cursor); cursor.close(); return newNote; } else { return null; } 4 [ad_2] solved Android cursor out of bounds exception

[Solved] Using java if-else [closed]

[ad_1] First, indicate to User the products available and their respective price: int productChoice = 0; int quantity = 0; double totalSum = 0.0; System.out.println(“Welcome To The Mail_Order House.”); System.out.println(“Please select Product Number (1 to 5) you want to buy:\n”); System.out.println(“1) Product Name 1: RM2.98”); System.out.println(“2) Product Name 2: RM4.50”); System.out.println(“3) Product Name 3: RM9.98”); … Read more

[Solved] What is “%20” as a string in curl data?

[ad_1] This is HTML encoding and %20 represents the space character. The string “searchText=sweet%20red%20wine” equates to “searchText=sweet red wine” Source: https://www.w3schools.com/tags/ref_urlencode.asp [ad_2] solved What is “%20” as a string in curl data?

[Solved] Java List not contains object [closed]

[ad_1] Your attempt won’t work since you’re handling the creation in the loop, so you will end up adding several persons there. Just write it the way you described it: if (allPersons.isEmpty() || !allPersons.contains(person)) allPersons.add(person) Now, in order for this to work you have to ask yourself an important question: What exactly constitutes “the same … Read more

[Solved] Word advancing in letters each new line

[ad_1] You got very close. You already had the idea to print the substring from 0 to i. Then you just need an inner loop that starts at i+1 and loops until word.length and print out the char at i. Also you need to use System.out.print() so that they will be on the same line: … Read more

[Solved] Comparator in Java [closed]

[ad_1] Java 8’s enhancements to the Comparator interface make it a lot more elegant: public static final Comparator<Student> BY_NAME = Comparator.comparing(Student::getName); public static final Comparator<Student> BY_Gpa = Comparator.comparingInt(Student::getGpa); [ad_2] solved Comparator in Java [closed]

[Solved] Java; looking for lowest Int [closed]

[ad_1] The problem was that you initialized some values that caused errors during the first iteration when you check for the smallest number. I added the following condition that will set the smallest number to the current number, but only during the first iteration. if (count2 == 1 || num < smalled ) { smalled … Read more

[Solved] Chain of responsibility – lambda function implementation [closed]

[ad_1] I have adapted the java example from the wikipedia article: In this example we have different roles, each having a fixed purchasing limit and a successor. Every time a user in a role receives a purchase request that exceeds his or her limit, the request is passed to his or her successor. A builder … Read more

[Solved] Retriving data from Firebase in Arraylist in Android [closed]

[ad_1] Assuming you have a model class for your electrician object named Electrician, to get a list of electrician objects, please use the following code: DatabaseReference rootRef = FirebaseDatabase.getInstance().getReference(); DatabaseReference electricianRef = rootRef.child(“Employee”).child(“Electrician”); ValueEventListener valueEventListener = new ValueEventListener() { @Override public void onDataChange(DataSnapshot dataSnapshot) { List<Electrician> list = new ArrayList<>(); for(DataSnapshot ds : dataSnapshot.getChildren()) { … Read more

[Solved] Submitting a search on a website using JAVA

[ad_1] The easiest way to do this requires getting an API key since MyFitnessPal’s API is private. You will want to submit a request to http://www.myfitnesspal.com/api and check ‘Pull from MFP food database’ in the “API Interest: ” section. If you’re approved and get the API key, then you will want to learn about basic … Read more

[Solved] Incompatible types; found: class java.lang.String, required: class java.io.ByteArrayOutputStream

[ad_1] You’re trying to assign the result of replaceAll (a String) to stream, a ByteArrayOutputStream. I think you mean to just create a new variable of type String: ByteArrayOutputStream stream= new ByteArrayOutputStream(); String str = stream.toString().replaceAll(“&lt;”,”<“); You can then convert the String to a byte array, using getBytes: byte[] bytes = str.getBytes(); 7 [ad_2] solved … Read more