You need to set isPrime to 0 each time the user enters a number. Otherwise, it still holds the value from the previous number. Move the variable declaration int isPrime = 0; inside the while loop. BTW, isn’t that variable name backwards? You set it to 1 (i.e. true) when you discover that there’s a … Read more
Let’s see. Assume first time it runs, x,y is 1,1. So you add Box(1,1). Next time is run, let’s assume x,y is 2,3. So, enter for loop: i = 0: Not same x,y, so enter else, and add Box(2,3). i = 1: Same as x,y (yeah, we just added it), so enter if and remove … Read more
you are missing type in event, check for type event.type; 2 solved JS – If Statements
No, that is an absolutely pointless use of exit(). If you absolutely need one, just put it at the end of the script. Using exit() like that is only useful if you provide an exit code (used in command line applications). solved What is the point of exit() after each if statement? [closed]
Without knowing why you want to use a single if, it’s hard to tell. Of course, you can use ternary operators without any ifs: unsigned int x, y; cin>>x; y = x<=1 ? 1 : x<=3 ? 2 : x<=5 ? 3 : 6; Or ugly boolean casting hacks for exactly one if (please don’t … Read more
So far, you have the right idea. I am going to assume based on your syntax, that you are using an array. Your get() method looks good, but you are missing some code from your remove() method. public int remove(int index){ //check for out-of-bounds if(index < 0 || index >= size) //assumes size is set … Read more
It can be done – however your function should be returning an int. int foo(void) { return 1; } int main(void) { switch(foo()) { case 0: printf(“foo\n”); break; case 1: printf(“bar\n”); break; default: break; } return 0; } As, can been seen this compiles and runs. [09:36 PM] $ gcc -Wall -Werror switcht.c -o switcht … Read more
if 0 in (result1, result2, result3): is equivalent to: if result1==0 or result2==0 or result3==0: What you want is this: if (0,0,0) == (result1, result2, result3): Which is equivalent to: if result1==0 and result2==0 and result3==0: You could actually even do this: if result1==result2==result3==0: since you’re checking to see if all 3 variables equal the … Read more
Parse error: syntax error, unexpected ‘else’ (T_ELSE) in C:\xampp3\htdocs\wb_html\login.php on line 8 [duplicate] solved Parse error: syntax error, unexpected ‘else’ (T_ELSE) in C:\xampp3\htdocs\wb_html\login.php on line 8 [duplicate]
BigDecimal use example vatTotalNoAgeLess5 = BigDecimal.valueOf(dinnerTotal).add(BigDecimal.valueOf(grossTick)).multiply(BigDecimal.valueOf(1.21)).doubleValue(); Example if statement if ((havingDinner.equals(“Y”) || havingDinner.equals(“y”)) && (ageDiscount.equals(“Y”) || ageDiscount.equals(“y”))) { agetick = (grossTick * 0.85); dinnerTotal = dinnerPrice * (standTick + terraceTick); vatTotalForAge = ((dinnerTotal + agetick) * 1.21); System.out.println(vatTotalForAge); } else if ((havingDinner.equals(“Y”) || havingDinner.equals(“y”)) && (ageDiscount.equals(“N”) || ageDiscount.equals(“n”))) { dinnerTotal = dinnerPrice * (standTick + … Read more
To answer your first question. By doing an if statement in one line you are limited to one operation, so to speak. if(ret != 0) return false; Whilst using the curly brackets you are declaring a block with code operations. if(ret != 0) { /* do other stuff here */ return false; } There is … Read more
if Enter == “Yes” or “yes”: This is not how or works. This is interpreted as if (Enter == “Yes”) or “yes”:. In python, non-empty strings are always true, so all of the if statements like that will be true. I would suggest something like if Enter.lower() == “yes”: which takes care of all of … Read more
if v < e: v = e can be read: “If v is less than e, make v the value of e.” As above you should put a new line to make it read easier: if v < e: v = e solved Python : What is the purpose of a colon in an if … Read more
Have a think about how you can code simple mathematics into your program, I will start you off with an example. if (productCost >= 20 && productCost < 60) { discount = 0.9; } What this does is check if the cost of the product lies between 20 and 60 and if it does it … Read more
You need to write these conditions, (11<=type_c<=15) as (11<=type_c && type_c<=15). solved Logical errors and incorrect output when testing if an integer is in a range [duplicate]