The built-in function you seem to be looking for is str.translate: S.translate(table [,deletechars]) -> string Return a copy of the string S, where all characters occurring in the optional argument deletechars are removed, and the remaining characters have been mapped through the given translation table, which must be a string of length 256 or None. … Read more
Here is how I would solve this in Java: import java.util.HashMap; import java.util.Map; import java.util.Random; public class ChocolatePuzzle { private static final Map <String, Integer> solutions = new HashMap <String, Integer> (); private static final Map <String, Integer> bestMoves = new HashMap <String, Integer> (); private static int [] x; private static int k (int … Read more
It first builds a table of all the solvable boards, represented as numbers, that says how many steps from the solution that board is. Then it solves each test case by looking it up in that table. The time complexity per test case is constant. I doubt that there is anything in the standard library … Read more
Without knowing why you want to use a single if, it’s hard to tell. Of course, you can use ternary operators without any ifs: unsigned int x, y; cin>>x; y = x<=1 ? 1 : x<=3 ? 2 : x<=5 ? 3 : 6; Or ugly boolean casting hacks for exactly one if (please don’t … Read more
What is a good non-recursive algorithm for deciding whether a passed in amount can be built additively from a set of numbers? solved What is a good non-recursive algorithm for deciding whether a passed in amount can be built additively from a set of numbers?
Just ask any one of them the following question: If you were the opposite to what you are going to be when you answer this question, which would be the right way to go? If he’s the indecisive type in lying mode, he’ll have to tell you to go the wrong way because, as a … Read more
It is parsed as: b = (a++)++ + a; This is an invalid expression. The increment operator can’t be applied twice as (a++) isn’t an lvalue. The tokenizer isn’t context-aware and will match the longest token possible, so it is not parsed as the syntactically valid a++ + ++a. (That still would be invalid code, … Read more