i starts as 10, but is incremented to 11, before it is tested. m is being assigned a boolean result, so will be either 0 or 1. i is non zero so evaluates to true for a boolean expression, therefore, the expression after the || do not need to be evaluated, as || is a … Read more
Negate the returning value from string.equals(TestString): !string.equals(“ABC”) You better have a look at Logical Operators in Java solved How do I check in JAVA if a string is not equal to? [closed]
In your code, if (number == 10 || 11 || 12 || 13 || 14 || 15 || 16 || 17 ||18 || 19) is a wrong approach. You cannot chain the logical operator like that. As of now, because of the operator precedence, your code is essentially if ( (number == 10) || 11 … Read more
When you use the Boolean Operator or, only one of the conditions declared has to be true in order for it to return true. 3>=3 is true, so the whole expression is true. solved Can someone explain why print(“red” == “blue” or 3 >= 3) returns True [duplicate]
y = rand(20,3); Creates a matrix of uniformly distributed random numbers, y. aa= unidrnd(2,20,3) – 1; Creates a matrix of uniformly distributed random integers, that goes from 1 to 2, and then subtract one. Thus, aa is a matrix of 0s and 1s. val = ( aa & y<1.366e-04) | (~aa & y<8.298e-04); This line … Read more
If it helps you to understand, you can rewrite it from AND to OR: while (command != “quit” && command != “q”) { // do job } is equivalent to while (!(command === “quit” || command === “q”)) { // do job } https://en.wikipedia.org/wiki/De_Morgan%27s_laws 5 solved OR and AND operator confusion in Javascript [closed]
When we use || it will check if first condition is false then it will go to second condition and so on, however the moment it finds a true condition it will return 1. In this case 4 is true so it will not evaluate further statements here 1 && ++i and it will directly … Read more
|| or logical OR operator has a short-circuit property. It only evaluated the RHS is the LHS is FALSY. In your case, the evaluation of ++x produces a value of -2, which is not FALSY (0). Hence, the RHS is never evaluated. To break it down: m = ++i || ++j && ++k; >> m … Read more
! is the NOT (negation) logical operator. It transform a false to true and true to false. Boolean logical operators (C# reference) solved c# meaning of ! before a statement [closed]
Use else if. $a = 1; if($a === 1) { // do something } else if ($a === 2) { // do something else } Note that in most case the switch statement is better for that, like: switch($a) { case 1: // do something break; case 2: // do something else break; } or: … Read more
The first statement compares the variable ‘a’ to ‘1’, and if the variable ‘a’ is equal to ‘1’, then you will execute the block of code enclosed in brackets. Likewise, the first statement also compares the variable ‘b’ to ‘1’ and if equal will execute a block of code. The second expression evaluates two conditions, … Read more
First of all, put the javascript code between a <script></script> tag because javascript code will not run in an html <div></div> tag. Then, instead of x == 0||9||2, use x == 0 || x == 9 || x == 2. Kindly indent your code for easier readability. The || operator looks for conditions on the … Read more
You need to write these conditions, (11<=type_c<=15) as (11<=type_c && type_c<=15). solved Logical errors and incorrect output when testing if an integer is in a range [duplicate]
See Short-circuit evaluation. Essentially what’s happening is that as l++=3 which is not 0, it evaluates to True (only 0 would be False). Thus, the second part of the expression after || is not evaluated. 3 solved Output of the below C Code [duplicate]
It is just logic: whole expression combined by and is true only when both parts are true. So when your loop met first : character, expression is false and loop has been stopped. Based on your description, your code should look like while (!(json[z-2] == ‘s’ && json[z] == ‘:’)) { z++; } or equivalentely … Read more