#include <iostream> using namespace std; int main() { int a,b,i,result; cout << ” Enter a and b: ” << endl; cin >> a >> b; result = a; // At 0 sec result is a for (i=1; i<=b; i++) { result = result*2; // Doubles the result at every second cout <<result<< endl; } return … Read more
You can try this: for (int i=6; i>1; i–) { for (int j=0; j<i; j++) cout<<“*”; cout<<endl; } Output: ****** ***** **** *** ** 2 solved Print 6,5,4,3,2 characters separated by a new line in C++?
what is wrong with this loop Initial value of b fails this check. 2*b+1 < 5 So neither loop body, nor the increment are ever executed. consider 2*b +1 as 2*c +1, i just ask, is this condition is a valid loop condition Yes, you can put any valid javascript expression there. As long as … Read more
remove below code from toString() Scanner in = new Scanner(System.in); System.out.print(“Enter a name: “); name = in.next(); System.out.print(“Enter a meal: “); mealType = in.next(); You are already reading these from the for loop. Also, your do-while loop is all wrong. The condition doesn’t make sense. It should be option > 0 && option <4 3 … Read more
In the second argument it is actually ++i!=0, The loop is interpreted as for(++i;++i!=0;++i) If you start with a positive i or 0, it will be an infinite loop and will invoke undefined behavior when i reaches INT_MAX. If i was -Ve initially the loop may stop at a defined run. EDIT: As you changed … Read more
Okay. Thanks to @AshishJohn this question is now solvable. In the provided link you can see a define in the beginning which changes the syntax of for loops: #define for(i,a,b) for(i=a;i<b; i++) So for(j,0,np) will be converted by the preprocessor to: for (j=0; j<np; j++) which is a normal for loop. np is also declared … Read more
As usual there are many ways to do the task. For example you can use the following solution #include <iostream> int main() { const size_t M = 5; const size_t N = 10; int a[M][N]; for ( size_t i = 0; i < M; i++ ) { for ( size_t j = 0; j < … Read more
#include<stdio.h> #define MAX_SIZE_ALLOTED_TO_EACH_QUESTION 100 #define NUMBER_OF_QUESTIONS 10 int scoreList[NUMBER_OF_QUESTIONS]; // This array will contain the individual score for each answers to respective questions int i; void Extroversion(int scoreList[]){ // Let formula for this be E = 20 +(1)___-(3)___+(2)___-(4)___ int E = 20 + (scoreList[1] + scoreList[2]) – (scoreList[3] + scoreList[4]); printf(“\nExtroversion is the personality trait … Read more
The answer is: u[0] = 6, u[1] = 9, u[2] = 12 I will explain how the loop goes. for (int i = 0; i < u.length; i++){ u[i] = b[0][i]; for (int j = 1; j < b.length; j++) u[i] += b[j][i]; } First loop: outer for loop: u[i] = b[0][i]; –> u[0] = … Read more
Based on what you’ve shown: testNum is greater than scores.length. This means that when you traverse the array by comparing your iterator (i) to testNum rather than its actual length, you will hit indexes which don’t exist. For example, let’s say testNum = 8 and scores.length = 5. Then in your code, you will get … Read more
Can u try this ? I added to logical solution to code.I changed only starting game and ending game properties’s lines. public class ChoHan { public static void main(String[] args) { final int MAX_ROUNDS = 5; String player1Name; String player2Name; Scanner keyboard = new Scanner(System.in); char repeat; do { System.out.println(” Enter the first player name … Read more
Any decent compiler will not penalize you for which ever version you use. As you can see, all the loops boil down to the same code, with maybe one instruction reordered. Go for the one that is most readable and clearly conveys what you want to do. If you are interested in what happens at … Read more
Basically, what you’re trying to do is group your data by group property, and then form some HTML out of it. Grouping is easy, then just use whatever language you’re comfortable with to build the html: const list = [{ ‘name’: ‘Display’, ‘group’: ‘Technical details’, ‘id’: ’60’, ‘value’: ‘Something’ }, { ‘name’: ‘Manufacturer’, ‘group’: ‘Manufacturer’, … Read more
In general, if you need to load a bunch of small data, its better to have one server endpoint that returns the all the data. It’s simpler for the client side and avoids the overhead of many xhrs. If you have 100 tags, do you really want to invoke 100 xhrs to get them all, … Read more
The question may be a case of “I have X and I need Y” where X is the item which needs attention. If the string really is as you presented it, then Imports System.Text Module Module1 Sub Main() Dim s = “{ “”0″”:{“”variable1″”:””ABC1″”,””variable2″”:””AA””,””variable3″”:””BB””}, “”5″”:{“”variable1″”:””ABC2″”,””variable2″”:””AA””,””variable3″”:””BB””}, “”3″”:{“”variable1″”:””BC3″”,””variable2″”:””AA””,””variable3″”:””BB””}, “”1″”:{“”variable1″”:””DC4″”,””variable2″”:””AA””,””variable3″”:””BB””}, “”4″”:{“”variable1″”:””DD5″”,””variable2″”:””AA””,””variable3″”:””BB””} }” Dim t = s.Split({vbCrLf}, StringSplitOptions.None) Dim u … Read more