You could do this, but you probably shouldn’t: def forn(n): def new_func(func): for i in range(n): func(i) return func return new_func @forn(10) def f(i): print(i) or this: def forn(n, func) return [func(i) for i in range(n)] x = forn(10, lambda x: x**2) But these are more verbose and less readable than for i in range(10): … Read more
You can sequentially loop through the string and append the inverted character to another string. You can check whether the character is lowercase or not by converting it to lowercase (with String.toLowerCase) and checking whether the result is equal to the original. let swappedName = “elZerO”; let res = “”; for (let i = 0; … Read more
After 4 days of trying I found the answer myself. Thanks for the great help guys… import numpy DARK = [] a = [] stack = [] for i in range(0,3): # create 3d numpy array d = numpy.array([[1, 2], [3, 4]]) a.append(d) stack.append(numpy.array(a)) # write it into the actual variable DARK.append(numpy.array(numpy.median(stack[i], 0))) solved python2.7 … Read more
concentrate on this piece of code for (i = 0; i <= 5 ;i++) { –> for (space = 5 – i; space <= 4; space++) { printf(” “); } in first iteration of inner for loop space value is space: 5-0 = 5 as the i:0 and for we have condition space <= 4 … Read more
If you have an array declared like int a[N]; where N is some positive integer value then the valid range of indices to access elements of the array is [0, N). It means that for example this for loop for(i=1;i<=10;i++) { printf(“enter 10 nos. for arr[%d] :”,i); scanf(“%d”,&arr[i]); } must look like for ( i … Read more
java.util.Scanner is probably what you’re looking for. As for the for loop, you should google Java for loop and read up on how they work. Then combine the two concepts. solved How to iterate a for loop for a user input amount of times Java [closed]
You add by using the += operator: for (i = 1; i <= n; i++) total += i; cout << total; Note this is short for total = total + i. 3 solved for-Loop to add integers [closed]
If I understood you code and data correctly, each item in pin_configuration begins with the target index, and then the indices to set to True. In python3, using extended iterable unpacking, you can do the following: for r, *indices in pin_configuration: for j in indices: bool_list[r – 1][j – 1] = True to adapt it … Read more
There is no such syntax in Python. The closest to one line you can get is two lines: lst = [1, 1, 2, 2, 2, 3, 3] uniq = [] for i in lst: if i not in uniq: uniq.append(i) # <—- else: continue # <—- print(str(i)) # other useful code Trying to put everything … Read more
You will have to use some mathematics here. Lets talk about your 2nd and 3rd loop: No of iterations in 3rd loop(for c) for each iteration of 2nd loop(for b): 1 = 2^0 ( for b < 1) 2 = 2^1 ( for b < 2) 4 = 2^2 ( for b < 4) . … Read more
Introduction Analysis complexity is an important concept in computer science, as it helps to determine the efficiency of algorithms. In particular, the analysis of complexity in a for inside for loop is important, as the complexity of the second for loop depends on the first one. This article will discuss the analysis of complexity in … Read more
How about: foreach(array(458752, 131586, 65793) as $x) { $j = intval($x / 65536); $x = $x % 65536; $i = intval($x / 256); $k = $x % 256; echo “x=$x, i=$i, j=$j, k=$k\n”; } output: x=0, i=0, j=7, k=0 x=514, i=2, j=2, k=2 x=257, i=1, j=1, k=1 2 solved PHP value=arraykey + arraykey + arraykey … Read more
Individual parameters aren’t iterable; you’d need a collection for that. Try changing it to an array instead: public void increment(int increment1, int increment2, int increment3) { int[] array = {increment1, increment2, increment3}; for(int i = 1; i < array.length; i++){ array[i] = 1; } } or public void increment(int[] increment) { for(int i = 1; … Read more
You explicitly ask the compiler to generate unoptimized code with -O0. The result is indeed rather slow as the nested loops do not get optimized away. The java compiler probably does that and removes the empty loops, a rather easy optimization. If you could require the java compiler to generate unoptimized byte code and prevent … Read more
myList = [] while True: word = input(“Enter a Word (Type ‘q’ to quit): “) if word == ‘q’: break myList.append(word) print(myList) RESULT Enter a Word (Type ‘q’ to quit): cat Enter a Word (Type ‘q’ to quit): dog Enter a Word (Type ‘q’ to quit): rat Enter a Word (Type ‘q’ to quit): q … Read more