Binary floating point math is like this. In most programming languages, it is based on the IEEE 754 standard. The crux of the problem is that numbers are represented in this format as a whole number times a power of two; rational numbers (such as 0.1, which is 1/10) whose denominator is not a power … Read more
Casting to integer (Int32) drops the fractional part of your number… int number = (Int32) 3.14159; // value of number will be 3 (not 3.14159) // Do this instead double c = Math.Sqrt(c2); // will give you the result you want output.Text = Convert.ToString(c); solved C# – Math.Sqrt() returning decimals
how to input floating point numbers in assembly language… and how to add subtract and multiply these floating point numbers [closed] solved how to input floating point numbers in assembly language… and how to add subtract and multiply these floating point numbers [closed]
Your code is equivalent to: double x1 = 0.9; float xf = (float)x1; // discard some precision double x2 = (double)xf; if (x2 >= x1) { // … } The problem is that, after you discarded some precision from x1 by converting it to float, it can never be recovered; casting it back to double … Read more
The comment in the link says “integer, pointer and member pointer template parameters aren’t lvalues” (emphasis mine). It does not say that named integer variables are not lvalues – they are. If there were such a thing as floating-point template parameters, then they wouldn’t be lvalues either; but named floating-point variables still would be. solved … Read more
Nothing to stop this float fun(float a) { cout << fixed << setprecision(1); return a; } But that’s stupid code for a stupid puzzle. What does this have to do with real programming? 3 solved How to add decimal to floating point number with non-decimal value [closed]
float x,i=~(257<<23),a,s,t;main(int n,char**f){a=-i;f=fopen(f[1],”r” );for(n=0;fscanf(f,”%f”,&x)>0;n++,s+=x,x<i?i=x:0,x>a?a=x:0,t+=x*x); printf(“%d %f %f %f %f\n”,n,a,i,s/n,sqrtf(t/n));} Sorry for the long code. Didn’t have time to make it shorter. 1 solved Read file with floats, calculate size, max, min, mean, median and standard deviaton in C [closed]
You are multiplying a list by a float. You should multiply each row of the matrix with words. Something like this will work. multiply_nonspam_test = [] for row in transpose_test_feature: multiply_nonspam_test.append([x*y for x,y in zip(row, log_train_probs_nonspam_words)]) print multiply_nonspam_test 0 solved can’t multiply matrix and list which type ‘float’
If you consult the documentation for printf in C and System.out.println in Java, you will see that they format output in different ways. This is because they are totally different, and I’m not sure why you expected them to produce the same results. If you want printf-style formatting in Java, consider using String.format() to format … Read more
OP tagged C++ so here goes.. std::stringstream ss; ss << f1; std::string s = ss.str(); ptr = s.c_str(); 3 solved How to convert float to string using single char pointer? [closed]
It is like below. bool Compare<T>(T x, T y) where T : class { … } So x and y should be of the same datatype. then only it can be compared. Decimal is 128 bits and single is 32 bits. Decimal is Decimal floating point and Double is Binary floating point. 2 solved == … Read more
We can understand what’s going on by looking at the anatomy of a 32-bit float. The value 3.0E9 in IEEE754 format is 0x4F32D05E, with exponent value 31 (you can use this online calculator to find the value). Now we have 23 sub-unity binary digits left for the mantissa. That means that the smallest increment, i.e. … Read more
When you use integer numbers in a division, the compiler understands that it has to perform an integer division. std::cout << 4 / 3; That means that 4 divided 3 equals 1, and the rest can be obtained by doing 4 % 3 (that’s the modulo operator) If you want to get a floating point … Read more
Sure the problem of PHP floating point precision was a topic on SO quite often, still I cannot see why this questions albeits 18 downvotes as the questionare asked very precisly for a concrete problem with a concrete floating point number. I have solved this in a way that everybody should understand clearly what the … Read more
You cannot convert an integer bitpattern to a float by means of a cast. That just converts the integer to the nearest floating-point number, it does not re-interpret the bits as being a float. If it worked like you think, this: const float x = 512; would set x to 7.175E-43, which would not be … Read more