Works in Python 3.x import random players = [“Player 1”, “Player 2″] for p in players: x = len(p) dice = random.randint(0, x*2) print(str(p) + ” rolls a ” + str(dice) + ” out of ” + str(x*2)) if dice > x: print(p + ” wins!”) elif dice == x: print(p + “gets a tie.”) … Read more
Just what the error says! You haven’t passed enough arguments: This prototype: fp(double a, double b, double c, double x) { means you need to pass four arguments, like: fp(x1, what, about, these); The same goes for newton. Also, regarding if (fp(x1)==0.0) – While floating point zero values can be compared with each other (zero … Read more
Instead of turning them off why not just redeclare it? If you turn the warnings off completely then you lose the fact that the compiler will give you warnings in genuine places. So just declare it above the unit test @interface NSDate (UnitTests) // your method sig @end @implementation YourUnitTest //… 3 solved Disabling *No … Read more
As the error says, you have int max declared twice. You need to change the second one to a variable assignment, not declaration: int max = i; for(int j = i+1; j < 1; j++) { if (wholeNumber[j] > wholeNumber[max]) { max = j; // NOT: int max = j; } } 0 solved Java: … Read more
This could be that the compiler is not seeing the included header file. for statement #include <conio.h> make sure your conio.h header file is in your compilers directory. else you can use #include “conio.h” and place the header file conio.h in the current project directory. This header declares several useful library functions for performing “console … Read more
Introduction Operator overloading is a powerful feature of C++ that allows you to redefine the behavior of operators for user-defined types. However, when using operator overloading, you may encounter errors such as “no match for ‘operator>>’”. This error occurs when the compiler cannot find a suitable definition for the overloaded operator. In this article, we … Read more
You have to change the get_name() to return a non-const reference, like string& get_name(); to get it working/compile. But will look strange. What you can do instead is pass the member name directly iss >> employee.name; that’s what friends do. And don’t forget to return the stream is. 1 solved Operator Overloading Error: no match … Read more
The printf function has the following declaration: int printf(const char *format, …); The first argument must be a pointer to a char array, but any additional arguments can be of any type, so it’s not a compiler error if a format specifier mismatches the parameter (although it is undefined behavior). This still works however because … Read more
You can avoid a circular include problem by using a forward declaration of a class instead of an #include: #ifndef ENTRANCE_H #define ENTRANCE_H #include <vector> #include “Diodio.h” class Segment; class Entrance { public: Entrance(); ~Entrance(); void operate(); protected: Segment *givesEntryTo; std::vector<Diodio> elBooths; std::vector<Diodio> manBooths; private: }; #endif // ENTRANCE_H (Entrance.cpp may or may not need … Read more
I don’t know what you are trying to do, but *= doesn’t appear to do what you think it does. *= is an assignment operator. It evaluates its left-hand side and its right-hand side, multiplies them together, and assigns the result to the result of its left-hand side. The result of a + b is … Read more
First of all, you need to decide whether you’re writing C or C++. C does not support classes, and you should not use C-style strings, I/O, and memory management routines in C++ code. Mixing elements of the two languages is a recipe for heartburn. C and C++ are completely different languages that happen to share … Read more
The problem is that the compiler tells me that he “cannot resolve the method beStored(int). That simply means that you’re attempting to pass an int type to the beStored method. If you look at the interface definition of this method again you’ll notice that you’re not obeying the contract that has been set. public void … Read more
Use QString as primary string type: QString result = QString(“apg -q -n %1 -x %2 -y %3”).arg(n).arg(x).arg(y); Or use a QTextStream to assemble everything. QString result; QTextStream ts(&result); ts << “apg -q -n ” << n << ” -x ” << x; To use std::string with .arg(): std::string x = “xxx”; QString result = QString(“xxx … Read more
First let’s simplify the problem to a Minimal Complete and Verifiable example that duplicates the problem: int try; Not much code is required because try is a reserved word. You cannot use try in a program without the compiler expecting a try/catch` block. Solution: Do not use try as an identifier. Instead use try_func or … Read more
You’re calling this a “cuda fortran” code, but it is syntactically incorrect whether you want to ultimately run the subroutine on the host (CPU) or device (GPU). You may wish to refer to this blog post as a quick start guide. If you want to run the subroutine increment on the GPU, you have not … Read more