You need to write it like this: func collectionView(_ collectionView: UICollectionView, cellForItemAt indexPath: IndexPath) -> UICollectionViewCell { let cell = collectionView.dequeueReusableCell(withReuseIdentifier: “MenuCollectionViewCell”, for: indexPath) as! MenuCollectionViewCell return cell } 3 solved Editor placeholder in source file swift [duplicate]
When you call round() with double agrument you actually call: double round(double x); from <cmath> not your version hence the error. If you rename your function error would be gone without cast. Yet another reason to avoid using namespace std. 1 solved C++ function returning wrong data type
I didn’t read your problem definition but your code sould be at least like this to be correct as syntax and logic: #include<stdio.h> float totalFee = 0; int hours = 0; int main(void) { int i; int b; printf(“Please Enter Number of Cars “); scanf(“%d”, &i); for (b = 0; b < i; b++) { … Read more
I pasted your code on https://tio.run/#c-gcc, and here’s the result: main prototype .code.tio.c:3:7: warning: ‘main’ takes only zero or two arguments [-Wmain] int main(int fib) { ^~~~ the main function prototype is int main(void) or int main(int argc, char *argv[]) Since you want user to input a number, you can choose the first form. count … Read more
Modify your addNumbers to return a value. Function signature states it returns int, so you must return int from the function. using System; public class Test { public static int addNumbers(int num1, int num2) { int result; result = num1 + num2; return result; } public static void Main() { int a = 2; int … Read more
void is not a complete type. It is only used either in a function definition to state that it either takes no parameters or returns no value, or as a generic pointer i.e. void *ptr. As such, a variable of type void cannot exist. solved C: error: array has incomplete element type ‘void’ [closed]
The are two errors (compile time errors, at least). First of all, cin, cout and endl are not known, you have to write them as std::cin, std::cout and std::endl. The second problem is here: switch (choice); Remove that semicolon and it’s fine. The reson why it’s not working with the semicolon is because then switch … Read more
I managed to fix this by changing type of ts to String and using to_string(). I think ts, being an &str, was a reference to data of v2, so it was impossible to drop v2 without also dropping ts. 2 solved Temporary value dropped while borrowed (E0506)